If I am correct the answer would be iron and nickel.
Answer:
Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²
Step-by-step explanation:
Step 1. Locate barium in the Periodic Table.
It's in Period 6, Group 2: Element 56 (highlighted blue in the Periodic Table below).
Step 2. Add 54 electrons to the energy levels
You add then in the order shown in the diagram below.
The complete electron configuration is:
Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²
n = 2 + 8 + 8 + 18 + 18 + 2 = 56
<span>The correct answer is, Alkali Metals</span>
Answer:
PCl₅ = 0.03 X 208 = 6.24g
PCl₃ = 0.05 X 137 =6.85 g
Cl₂ = 0.03X71 = 2.13 g
Explanation:
The equilibrium constant will remain the same irrespective of the amount of reactant taken.
Let us calculate the equilibrium constant of the reaction.
Kc=![\frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BPCl_%7B3%7D%5D%5BCl_%7B2%7D%5D%7D%7B%5BPCl_%7B5%7D%5D%7D)
Let us calculate the moles of each present at equilibrium

molar mass of PCl₅=208
molar mass of PCl₃=137
molar mass of Cl₂=71
moles of PCl₅ = 
moles of PCl₃= 
moles of Cl₂ = 
the volume is 5 L
So concentration will be moles per unit volume
Putting values
Kc = 
Now if the same moles are being transferred in another beaker of volume 2L then there will change in the concentration of each as follow

Initial 0.02 0.06 0.04
Change -x +x +x
Equilibrium 0.02-x 0.06+x 0.04+x
Conc. (0.02-x)/2 (0.06+x)/2 (0.04+x)/2
Putting values
0.024 = 
Solving



x = -0.01
so the new moles of
PCl₅ = 0.02 + 0.01 =0.03
PCl₃ = 0.06-0.01 = 0.05
Cl₂ = 0.04-0.01 = 0.03
mass of each will be:
mass= moles X molar mass
PCl₅ = 0.03 X 208 = 6.24g
PCl₃ = 0.05 X 137 =6.85 g
Cl₂ = 0.03X71 = 2.13 g
Answer:
Mass = 1785.6 g
Explanation:
Given data:
Moles of lead oxide = 8 mol
Mass in grams = ?
Solution:
Formula:
Number of moles = mass/ molar mass
Mass = number of moles × molar mass
Molar mass of PbO = 223.2 g/mol
Now we will put the values.
Mass = 8 mol × 223.2 g/mol
Mass = 1785.6 g
Thus 8 moles of lead oxide have 1785.6 grams.