The grams of aluminum that are required to produce 3.5 moles of AlO3 in presence of excess O2 is calculated as below
write the equation for reaction
4 Al + 3O2 =2 Al2O3
by use of mole ratio between Al to Al2O3 which is 4 :2 the moles of Al
=3.5 x4/2 = 7 moles
mass of Al = moles / x molar mass
= 7 moles x27 g/mol =189 grams
1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure. Details about moles can be found below.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
At STP;
- T = 273K
- P = 1 atm
- R = 0.0821 Latm/molK
1 × 35 = n × 0.0821 × 273
35 = 22.41n
n = 35/22.41
n = 1.56mol
Therefore, 1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure.
Learn more about number of moles at: brainly.com/question/14919968
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