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coldgirl [10]
3 years ago
12

given the balanced equation representing a reaction: 2H2 O2 = 2H2O, what is the total mass of water formed when 8 grams of hydro

gen reacts completely with 64 grams of oxygen?
Chemistry
1 answer:
Vadim26 [7]3 years ago
3 0
The reaction equation represents the mole number ratio. So the hydrogen is 8/2=4 mol. Oxygen is 64/32=2 mol. So the water is 4 mol. The mass of water is 4*18=72 g. Or if it is confirmed that they are completely reacted. You can simply add them up.
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If 8.00 g NH4NO3 is dissolved in 1000 g of water, the water decreases in temperature from 21.00 degrees Celsius to 20.39 degrees
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Answer:

25.7 kJ/mol

Explanation:

There are two heats involved.

heat of solution of NH₄NO₃ + heat from water = 0

q₁  +  q₂  =  0

n  =  moles of NH₄NO₃  =  8.00 g NH₄NO₃  ×  1 mol NH₄NO₃/80.0 g NH₄NO₃          

∴ n =   0.100 mol NH₄NO₃

q₁ = n * ΔHsoln = 0.100 mol * ΔHsoln

m  =  mass of solution  =  1000.0 g + 8.00 g  =  1008.0 g

q₂  =  mcΔT  = 58.0 g  ×  4.184 J°C⁻¹  g⁻¹  × ((20.39-21)°C) = -2570.19 J

q₁  +  q₂  =  0.100 mol  ×ΔHsoln  – 2570.19 J  =  0

ΔHsoln  =  +2570.19 J  /0.100 mol  =  +25702 J/mol  =  +25.7 kJ/mol

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Answer: K_{eq} for the reaction is 5.55

Explanation:

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The given balanced equilibrium reaction is,

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At eqm. conc.   (0.010) M     (0.15)  M   (0.37) M

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Now put all the given values in this expression, we get :

K_c=\frac{(0.37)\times (0.15)}{(0.010)}

K_c=5.55

Thus the K_{eq} for the reaction is 5.55

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