Answer: The pH of an aqueous solution of .25M acetic acid is 2.7
Explanation:

cM 0 0
So dissociation constant will be:

Give c= 0.25 M and
= ?

Putting in the values we get:


![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
![[H^+]=0.25\times 0.0084=0.0021](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.25%5Ctimes%200.0084%3D0.0021)
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![pH=-log[0.0021]=2.7](https://tex.z-dn.net/?f=pH%3D-log%5B0.0021%5D%3D2.7)
Thus pH is 2.7
Answer:
This question sadly does not make much sense, please rephrase it.
<span>he specific heat capacity of liquid water is 4.186 J/gm K.</span>
-2 cuz 20 negative minus 18 positive is -2