Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm
Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side
For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm
If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm
Answer:
243 or 3^5
Step-by-step explanation:
You can do the product by multiplying starting from the left.
3 * 3 * 3 * 3 * 3 =
= 9 * 3 * 3 * 3
= 27 * 3 * 3
= 81 * 3
= 243
You can also change it to an exponential form.
3 * 3 * 3 * 3 * 3 = 3^5
the numbers are 6 and 13
let x be one of the numbers then the other is 2x + 1
their sum increased by 7 = 26
x + 2x + 1 + 7 = 26
3x + 8 = 26
subtract 8 from both sides
3x = 26 - 8 = 18
divide both sides by 3
x = 
= 6
the numbers are 6 and (2 × 6) + 1 = 12 + 1 = 13
Answer:
UwU UwU UwU UwU
Step-by-step explanation:
