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Readme [11.4K]
3 years ago
9

Write each phrase as an algebraic expression.

Mathematics
1 answer:
german3 years ago
8 0
N/8, 4p, b+14, 90x, -16, 24-k, 3(w), 1+q, 13/z, 45+c, w-8
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Which equation can be used to find the area of the blue triangle?
kvv77 [185]
Answer: B) A=1/2(7)(12).

Explanation: The formula for area of a triangle is 1/2bh. Only B maintains this formula.
5 0
2 years ago
Read 2 more answers
The width of a rectangle is the length minus 2 units. the area of the rectangle is 35 units
Mariana [72]

Answer:

Length=7units\\\\Width=5units

Step-by-step explanation:

Width=(Length-2) units

W=(L-2) units

Area of the rectangle= 35 square units

Area = length* Width

35= L*(L-2)\\\\35=L^2-2L

Subtracting 35 both sides:

L^2-2L-35=0

Solving the quadratic equation for 'L' ;

Using factorization:

L^2+5L-7L-35=0

Taking common from the equation :

L(L+5)-7(L+5)=0\\\\(L+5)(L-7)=0\\\\L+5=0\\\\L=-5

OR

L-7=0\\\\L=7

The length cannot be negative, therefore Length(L)= 7

Width=Length-2\\\\=7-2\\\\=5 units

Length=7units\\\\Width=5units

8 0
3 years ago
Lim x--> 0 (e^x(sinx)(tax))/x^2
Tom [10]

Make use of the known limit,

\displaystyle\lim_{x\to0}\frac{\sin x}x=1

We have

\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)

since \tan x=\dfrac{\sin x}{\cos x}, and the limit of a product is the same as the product of limits.

\dfrac{e^x}{\cos x} is continuous at x=0, and \dfrac{e^0}{\cos 0}=1. The remaining limit is also 1, since

\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1

so the overall limit is 1.

4 0
3 years ago
How do you do this problem 2/5+4a=-6/5 what does A = to?
a_sh-v [17]

Answer: A = -2/5

Step-by-step explanation:

- 6/5 - 2/5 = - 8/5 aka - 1 3/5

-1 3/5 ÷ 4 = - 2/5

4 0
3 years ago
How to solve this problem??
slega [8]
\frac{2}{3} =  \frac{18}{x+5}

multiply each side by x+5
\frac{2x+10}{3}=18
multiply each side by 3

8 0
3 years ago
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