Suppose cotangent (theta) = startfraction 5 over 12 endfraction, where pi less-than theta less-than startfraction 3 pi over 2 en
1 answer:
sin(Q) = -(12/13)
<h2>What are trigonometric ratios?</h2>Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle. The basic trigonometric ratios are sin, cos, and tan, namely sine, cosine, and tangent ratios. The other important trig ratios, cosec, sec, and cot, can be derived using the sin, cos, and tan respectively. It is a branch of mathematics that deals with the relation between the angles and sides of a right-angled triangle.
cot(Q) = 5/12
sin(Q) = 1/cosec(Q)
sin(Q) = ±12/13
Because, π < Q < (3/2)π
Therefore, sin(Q) = -12/13
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<u>Correct </u><u>Inputs </u><u>:-</u>
In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC
Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.
Median is the line segment from a vertex to the midpoint of the opposite side.
<u>Let us Check all options one by one </u>
- CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌
- BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️
- AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️
- AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌
- AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️