Suppose cotangent (theta) = startfraction 5 over 12 endfraction, where pi less-than theta less-than startfraction 3 pi over 2 en
1 answer:
sin(Q) = -(12/13)
<h2>What are trigonometric ratios?</h2>Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle. The basic trigonometric ratios are sin, cos, and tan, namely sine, cosine, and tangent ratios. The other important trig ratios, cosec, sec, and cot, can be derived using the sin, cos, and tan respectively. It is a branch of mathematics that deals with the relation between the angles and sides of a right-angled triangle.
cot(Q) = 5/12
sin(Q) = 1/cosec(Q)
sin(Q) = ±12/13
Because, π < Q < (3/2)π
Therefore, sin(Q) = -12/13
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A function 
is periodic if there is some constant 
such that 
for all 
in the domain of . Then is the "period" of .
Example:
If
, then we have 
, and so 
is periodic with period 
.
It gets a bit more complicated for a function like yours. We're looking for such that
Expanding on the left, you have
and
It follows that the following must be satisfied:
The first two equations are satisfied whenever
, or more generally, when 
and 
(i.e. any multiple of 4).
The second two are satisfied whenever
, and more generally when 
with (any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:
More generally, it can be shown that
is periodic with period
.
Example:
If
It gets a bit more complicated for a function like yours. We're looking for
Expanding on the left, you have
and
It follows that the following must be satisfied:
The first two equations are satisfied whenever
The second two are satisfied whenever
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when
Let's verify:
More generally, it can be shown that
is periodic with period
Hi there! :)
<u>Answer:</u>
Subtract 43 from 20 raised to the 7th power; then multiply by 3. The answer is: <u>3,839,999,871</u>
Step-by-step explanation:
"Subtract" means to take away a number from another.
" 20 raised to the 7th power" is the same thing as 20 exponent 7:
SO, you want to take away 43 from and then multiply the answer by 3:
( - 43) × 3
1,280,000,000
(1,280,000,000 - 43) × 3
1,280,000,000 - 43 = 1,279,999,957
1,279,999,957 × 3
1,279,999,957 × 3 = <u>3,839,999,871</u>
There you go! I really hope this helped, if there's anything just let me know! :)