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Digiron [165]
2 years ago
6

Suppose cotangent (theta) = startfraction 5 over 12 endfraction, where pi less-than theta less-than startfraction 3 pi over 2 en

dfraction. what is sin(θ)?
Mathematics
1 answer:
Nimfa-mama [501]2 years ago
4 0

sin(Q) = -(12/13)

<h2>What are trigonometric ratios?</h2>

Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle. The basic trigonometric ratios are sin, cos, and tan, namely sine, cosine, and tangent ratios. The other important trig ratios, cosec, sec, and cot, can be derived using the sin, cos, and tan respectively.  It is a branch of mathematics that deals with the relation between the angles and sides of a right-angled triangle.

cot(Q) = 5/12

sin(Q) = 1/cosec(Q)

sin(Q) = \frac{1}{\sqrt{1+{cot}^2(Q)}}\\sin(Q) = \frac{1}{\sqrt{1+\frac{25}{144}}}\\sin(Q) = \frac{1}{\sqrt{\frac{169}{144}}}\\

sin(Q) = ±12/13

Because, π < Q < (3/2)π

Therefore, sin(Q) = -12/13

To learn more, Visit:

brainly.com/question/17895477

#SPJ4

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8 sandwiches cut into 4 pieces each gives you 32 pieces.
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Please help! Segment QR is tangent to circle P at point Q. What is the measure of angle PQR? A.) 37 degrees B.) 53 degrees C.) 9
Andrew [12]

Answer:

Correct option: C) 90 degrees

Step-by-step explanation:

When we have a tangent segment to a circle, the angle made with the radius of the circle and the tangent segment is always a right angle, that is, 90 degrees. In other words, the radius and the tangent segment are always perpendicular.

If QR is tangent to the circle P, and PQ is the radius of the circle, the segment PQ is perpendicular to the segment QR, so the angle PQR is equal 90 degrees.

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6 0
3 years ago
triangle ABC is isosceles, angle B is vertex angle , AB = 20x -2, AC =25x, and BC =12 x +20. Find x and the length of each side
lisov135 [29]

Length of AB = 18. 92

Length of AC = 26. 15

Length of BC = 32. 552

<h3>How to determine the sides of the triangle</h3>

Using the Pythagorean theorem, we have that

(20 x-2)^2 = (12x + 20)^2 + (25x)^2

Expand the bracket

400x^2- 4 = 144x^2 + 400 + 625x^2

Collect like terms

400x^2 - 144x^2 - 625x^2 = 400 + 4

-369x^2 = 404

Make x^2 subject

x^2 = \frac{404}{369}

x = \sqrt{1.0948}

x = 1. 046

Thus,

Length of AB = 20x -2 = 20(1. 046) - 2 = 18. 92

Length of AC = 25x = 25* 1.046 = 26. 15

Length of BC = 12x + 20 = 12(1. 046) + 20 = 32. 552

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