So you have 10 total cups and 5 batches. Assuming that the raisens are evenly distributed, you get 10/5, which is 2 raisin cups per batch
Step-by-step explanation:
We have y = sin(ax + b).
=> dy/dx = a * cos(ax + b)
=> d²y/dx² = a[a * -sin(ax + b)] = a² - a * sin(ax + b).
Therefore d²y/dx² = a² - ay,
d²y/dx² - a² + ay = 0.
Answer:
18r-4
Step-by-step explanation:
Here is your anwer
Answer:
0.8762 or 87.62%
Step-by-step explanation:
Since our mean is μ=14.3 and our standard deviation is σ=3.7. If we're trying to figure out what percentage is P(10 ≤ x ≤ 26) equal to we must first calculate our z values as such:
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Our x value ranges from 10 to 26 therefore let x=10 and we obtain:
![z=\frac{10-14.3}{3.7} =-1.16\\](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B10-14.3%7D%7B3.7%7D%20%3D-1.16%5C%5C)
If we look at our z-table we find that the probability associated with a z value of -1.16 is 0.1230 meaning 12.30%.
Now let's calculate the z value when x = 26 and so:
![z=\frac{26-14.3}{3.7}=3.16\\](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B26-14.3%7D%7B3.7%7D%3D3.16%5C%5C)
Similarly, we use the z-table again and find that the probability associated with a z value of 3.16 is 0.9992 meaning 99.92%.
Now we want to find the probability in between 10 and 26 so we will now subtract the upper limit minus the lower limit in P(10 ≤ x ≤ 26) therefore:
0.9992 - 0.1230 = 0.8762
or 87.62%
Answer:
Evaluate:
-
- ![\frac{5}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B8%7D)
Factor:
![\frac{5(-4a-3}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B5%28-4a-3%7D%7B24%7D)
Step-by-step explanation: