You cannot solve for x but you can factor
to solve in ax^2+bx+c form you must find
b=x+y
a times c=x times y
so solve
3 times 3=9
what 2 number multily to get 9 and add to get 10
9=x times y
the numbers are 9 and 1 so
3x^2+1x+9x+3
(3x^2+1x)+(9x+3)
factor
(x)(3x+1)+(3)(3x+1)
reverse distribute
ab+ac=a(b+c)
(x)(3x+1)+(3)(3x+1)=(x+3)(3x+1)
factored out form is (x+3)(3x+1)
Answer:
in 84 minutes or 1 hr, 24 min
Step-by-step explanation:
you need to find the least common multiple of 2, 3 and 28 which is 84
Answer:131
Step-by-step explanation:
hope this helps <3
