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yKpoI14uk [10]
3 years ago
13

About how many times larger is 9.8 x 10^8 than 5.2 x 10^5?

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

it is about 30 times larger

Step-by-step explanation:

I know because I am related to Albert Einstein and because I'm really smart. I have 2 awards for being smart.

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Find the probability of choosing a penny or a dime from 4 pennies 3 nickeles and 6 dimes
bezimeni [28]

Answer:

5.0/5

Step-by-step explanation:

4 0
3 years ago
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Plz help will be marked BRAINLIEST!!<br><br><br> Yed
Natasha2012 [34]

X=−13

Distribute

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divide both sides

then simplify again to arrive at your answer.

8 0
3 years ago
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Examine each number. What number can you add to this number to make a number that has a whole-number square root?
Fantom [35]

the answer is 470

Step-by-step explanation:Because 470+470 which equals 940 and the  square root is 30

3 0
3 years ago
A solid right pyramid has a regular hexagonal base with an area of 7.4 units2. The pyramid has a height of 6 units.
Lelechka [254]

Answer: Second option.

Step-by-step explanation:

You need to use the following formula:

V=\frac{1}{3}Bh

Where "B" is the area of its base and "h" is the height.

According to the data given in the exercise, you know that:

B=7.4 units^2\\\\h=6\ units

Therefore, knowing this values, you can substitute them into the formula shown before and then evaluate, in order to calculate the volume of thi right pyramid whose base is a regular hexagon.

Then, you get:

V=\frac{1}{3}(7.4 units^2)(6\ units)\\\\V=14.8\ units^3

6 0
3 years ago
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An equilateral ∆ has sides of length 16 cm. Find the length of an altitude.
inn [45]

The length of the altitude is 8\sqrt{3}

Explanation:

Let ABC be an equilateral triangle.

It has sides of length 16 cm

Let AD be the altitude of the triangle.

We need to determine the length of an altitude.

Let AC = 16 cm and CD = 8 cm

Let us consider the right angled triangle ADC

Using the Pythagorean theorem, we have,

AC^2=AD^2+DC^2

Substituting the values, we get,

 16^2=AD^2+8^2

 256=AD^2+64

 192=AD^2

8\sqrt{3}=AD

The length of the altitude is 8\sqrt{3}

5 0
3 years ago
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