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frutty [35]
3 years ago
15

(20 POINTS!!) Which Statement correctly explains why H2S is a stronger acid than water?

Chemistry
1 answer:
astra-53 [7]3 years ago
5 0

Answer:

a) is the answer

Explanation:

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The lengthening of a transmitted signal's wavelength and/or a decrease in its frequency, which indicates that the object is movi
Alla [95]

B

Relative to the observer, the objected, emitting visible light will appear red in color because the wavelength of light is stretched hence acquiring longer wavelength in the visible electromagnetic spectrum (remember red light has the longest wavelength in the visible light spectrum).

Explanation:

Conversely, if the object was moving towards the observer, it would appear blue in color (blue shift) because the relative wavelength of the visible light would be ‘compressed’ (remember this is always relative to the observer) hence the wavelength would be shorter (and blue light has the shortest wavelength in the visible light spectrum).

Both these phenomenons are classified under Doppler shift effect of waves. It also occurs in our daily lives. When a wailing ambulance approaches you, the pitch of the wailing sounds is higher (relative to you). However, when the ambulance passes you and begins stretching away from you, the pitch of the wailing goes low.

Learn More:

For more on Doppler shift effect check out;

brainly.com/question/3841958

#LearnWithBrainly

4 0
3 years ago
Read 2 more answers
Calculate the pH of 1.00 L of the buffer 0.95 M CH3COONa/0.92 M CH3COOH before and after the addition of the following species.
natima [27]

Answer: (a) pH = 4.774, (b) pH = 4.811 and (c) pH = 4.681

Explanation: (a) pH of the buffer solution is calculated using Handerson equation:

pH=pKa+log(\frac{base}{acid})

pKa for acetic acid is 4.76. concentration of base and acid are given as 0.95M and 0.92M. Let's plug in the values in the equation and calculate the pH of starting buffer.

pH=4.76+log(\frac{0.95}{0.92})

pH = 4.76 + 0.014

pH = 4.774

(b) When 0.040 mol of NaOH (strong base) are added to the buffer then it reacts with 0.040 mol of acetic acid and form 0.040 mol of sodium acetate.

Original buffer volume is 1.00 L. So, the original moles of sodium acetate will be 0.95 and acetic acid will be 0.92.

moles of acetic acid after addition of NaOH = 0.92 - 0.040 = 0.88

moles of sodium acetate after addition of NaOH = 0.95 + 0.040 = 0.99

Let's again plug in the values in the Handerson equation:

pH=4.76+log(\frac{0.99}{0.88})

pH = 4.76 + 0.051

pH = 4.811

(c) When 0.100 mol of HCl are added then it reacts with exactly 0.100 moles of sodium acetate(base) and form 0.100 moles of acetic acid(acid).

so, new moles of acetic acid = 0.92 + 0.100 = 1.02

new moles of sodium acetate = 0.95 - 0.100 = 0.85

Let's plug in the values in the equation:

pH=4.76+log(\frac{0.85}{1.02})

pH = 4.76 - 0.079

pH = 4.681

5 0
4 years ago
Which two particles are present in the nucleus of an atom?
Kamila [148]

Answer:

protons and neutrons are the answer

3 0
3 years ago
Read 2 more answers
Which statement accurately describes renewable energy sources?
Nikolay [14]

Answer:

D they are quickly replenished. I get this question a good bit so i know the answer.

Explanation:

7 0
4 years ago
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40.0% C, 6.72% H, 53.29%, O. Molar mass is 60 g/mol. Determine the empirical and molecular formula.
arsen [322]

Answer:

Molecular formula: C₂H₄O₂

Empirical formula: CH₂O

Explanation:

40 % C, 6.72 % H and 53.29 % O states the centesimal composition of the compound. These data means that in 100 g of compound we have x grams of a determined element.

We divide the mass by the molar mass of each:

40 g / 12 g/mol = 3.33 moles of C

6.72 g / 1 g/mol = 6.72 moles of H

53.29 g / 16 g/mol = 3.33 moles of O

We can determine rules of three to get, the molecular formula.

In 100 g of compound we have 3.33 moles of C, 6.72 moles of H and 3.33 moles of O; therefore in 60 g (1 mol) we must have

- (60 . 3.33) / 100 = 2 moles of C

- (60 . 6.72) / 100 = 4 moles of H

- (60 . 3.33) / 100 = 2 moles of O

Molecular formula is C₂H₄O₂

Empirical formula has the lowest suscripts; we divide by two, so the empirical formula is CH₂O

3 0
3 years ago
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