The answer is simulus check baby girl
Answer:
Nitrogen (N), carbon (C), hydrogen (H) and oxygen (O).
Explanation:
Hello,
Given the shown organic compound, we refer to types of atoms to the elements present in the compound, thus, we find nitrogen (N), carbon (C), hydrogen (H) and oxygen (O) that are bonded via single or double bonds in such compound.
Let's remember that compounds like that, having those elements are mainly found in biochemical substances such as proteins, a very important source of benefits for our body.
Regards.
I think the name for it due to research online is Phosphide
Answer:
i = 2.483
Explanation:
The vapour pressure lowering formula is:
Pₐ = Xₐ×P⁰ₐ <em>(1)</em>
For electrolytes:
Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ
Where:
Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)
4.5701g of MgCl₂ are:
4.5701g ₓ (1mol / 95.211g) = 0.048000 moles
43.238g of water are:
43.238g ₓ (1mol / 18.015g) = 2.400 moles
Replacing in (1):
0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm
0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)
2.4mol + i*0.048mol = 2.4mol / 0.9527
2.4mol + i*0.048mol = 2.5192mol
i*0.048mol = 2.5192mol - 2.4mol
i = 0.1192mol / 0.048mol
<em>i = 2.483</em>
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I hope it helps!
Based on the table and the equation of reaction; the
- rate of consumption of oxygen between time 20 and 40s is 0.005 M/s
- rate of consumption of oxygen between time 40 and 60s is 0.0025 M/s
<h3>What is rate of a reaction?</h3>
The rate of a reaction is the rate at which reactants molecules are consumed or products are formed.
- Rate of reaction = change in concentration of reactants or products/ time taken
Based on the equation of reaction, the rate of consumption of oxygen is equal to the rate of consumption of methane.
Thus. rate of consumption of oxygen from time 20 seconds to time 60 seconds is calculated as follows:
Rate between 20 and 40 = 1.0 - 0.9/20
- Rate of consumption of oxygen = 0.005 M/s
Rate between 40 and 60 = 0.9 - 0.85/20
- Rate of consumption of oxygen = 0.0025 M/s
Therefore, the rate of consumption of oxygen decreases with time.
Learn more about rate of reaction at: brainly.com/question/25724512
