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Zarrin [17]
3 years ago
15

Onic bonds are formed between metal and nonmetal elements. Potassium has only one valence electron and it is stripped away in th

e process of forming an ionic bond. Nonmetals, such as chlorine, tend to gain valence electrons in the formation of ionic bonds.
Determine which element(s) are likely to have their electrons stripped away in the formation of ionic bonds.

I) aluminum
II) sulfur
III) oxygen
IV) silver
V) neon
Chemistry
2 answers:
Veronika [31]3 years ago
6 0
The elements that would have electrons stripped away are those that have a positive charge. (Aluminum and silver)
Svetllana [295]3 years ago
6 0

Answer:

Aluminum and silver

Explanation:

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TRUE - FALSE
inessss [21]

Answer:

True

Explanation:

4 0
3 years ago
1.0 gallon to mm<br>N.B 1 gallon=3.8L​
I am Lyosha [343]

Answer:

Gallon (US) to Milliliter Conversion Table

Gallon (US) [gal (US)] Milliliter [mL]

1 gal (US) 3785.411784 mL

2 gal (US) 7570.823568 mL

3 gal (US) 11356.235352 mL

5 gal (US) 18927.05892 mL

4 0
3 years ago
Crude oil pumped out of the ground may be accompanied by formation water, a solution that contains high concentrations of nacl a
djverab [1.8K]

solution:

the change in the boiling point is given as,

dTbp =2.30°c

elevation constant for the solvent is given by,

kb=0.512°c/m

molality=\frac{dTBP}{KB\times m}\\=\frac{2.30}{0.512c/m}

= 4.49m

8 0
3 years ago
A mixture of carbon dioxide and hydrogen gases is maintained in a 6.68 L flask at a pressure of 2.14 atm and a temperature of 19
matrenka [14]

Answer:

The mass of hydrogen gas in the mixture: <u>w₂ = 0.433 g</u>

Explanation:

<u>According to the ideal gas equation: </u>

for an ideal gas, P.V = n_{total}.R.T

and n_{total}= n_{1}+n_{2}

Here, P: total pressure of the gases = 2.14 atm  

V: total volume of the gases = 6.68 L

T: temperature = 19 °C = 19+273.15 = 292.15K        (∵ 0°C = 273.15K)

R:  gas constant = 0.08206 L·atm·K⁻¹·mol⁻¹

n_{total}: total number of moles of gases

<u>To calculate the total number of moles of gases</u>:

n_{total} = \frac{P.V}{R.T} = \frac{2.14 atm\times 6.68 L}{0.08206 LatmK^{-}mol^{-}\times 292.15K} = <u>0.5963 moles</u>

Let, the number of moles of carbon dioxide be n₁ and number of moles of hydrogen be n₂

<u>Given:</u> mass of carbon dioxide: w₁ = 16.8 g, mass of hydrogen: w₂ = ?g

molar mass of carbon dioxide: m₁ = 44.01 g/mol, molar mass of hydrogen: m₂= 2.016 g/mol

Therefore, n_{total}= n_{1}+n_{2} =  (w₁ ÷ m₁) + (w₂ ÷ m₂)

⇒ 0.5963 mol =  (16.8 g ÷ 44.01 g/mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol =  (0.3817mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol - 0.3817mol = (w₂ ÷ 2.016 g/mol)

⇒ 0.2146 mol = (w₂ ÷ 2.016 g/mol)

⇒ w₂ = 0.433 g

<u>Therefore, the mass of hydrogen gas in the mixture: w₂ = 0.433 g</u>

4 0
4 years ago
What is the molar mass of CH20?
cluponka [151]

Answer:

30.026 <em>g/mol</em>

Explanation:

no explaination

4 0
3 years ago
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