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Svetllana [295]
2 years ago
13

JEEZUS PLEASE HELP ME PEOPLE KEEP TROLLING ME AND NONE OF MY ANSWERS HAVE BEEN CORECTLY ANSWERED, I WILL GIVE MONEY FOR FLIPS SA

KE IF YOU HELP!!!!

Mathematics
1 answer:
Savatey [412]2 years ago
8 0

Answer:

14. 6 x 10^{17}

15. 28.615 x 10^{10}

16. I'm so sorry, I'm not sure!

17. 1.26 x 10^{10}

18. 1.639 x 10^{-8}

19. 2.025 x 10^{17}

<em>Hope that helps! I'm sorry if it's wrong, and sorry about all the trouble that has been brought upon you!</em>

<em></em>

<em>-Aphrodite</em>

Step-by-step explanation:

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What is the m∠2 if m∠4 = 81° and m∠3 = 40°?<br> a. 40°<br> b. 59°<br> c. 41° <br> d. 60°
velikii [3]

Answer:

C. 41

Step-by-step explanation:

180 - 81 = 99

99+40 = 139

180 -139 = 41

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3 years ago
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Explain why 4/10 and 40/100 have unlike denominators but are equivalent fractions
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4/10 and 4/100 are the same because all you had to do was multiply both the numerator and denominator by 10. It is still the same amount. Hope this helps!
5 0
3 years ago
0.003 is 1/10 of which decimal
12345 [234]
The correct answer would be 0.1
6 0
3 years ago
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The following box plot represents the average heights of the students in Mrs. Hill's sixth grade math class.
Svetllana [295]

Answer:

Step-by-step explanation:

Half of the students in Mrs. Hill's class are between 147 centimeters and 154 centimeters tall. (correct)

The median height of the students in Mrs. Hill's class is 152 centimeters. (correct)

The interquartile range of this data set is 15 centimeters.  (incorrect, 154-147=17 cm)

The mean height of the students in Mrs. Hill's class is 152.5 centimeters.  (we don't get to know the mean height from the graph).

6 0
3 years ago
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Need help with #1 #4 #7 plz giving 15 points
valentina_108 [34]

Answer:

Q1:  p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{8} \hspace{1mm}  \textbf{=} \hspace{1mm} \textbf{3}

We solve this taking LCM.

We get: $ \frac{-p - 24}{3} = 3 $

$ \implies - p - 24 = 9 $

$ \implies \textbf{p} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 33} $

Q4: $ \frac{\textbf{d}}{\textbf{11}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{4} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Again we proceed like Q1 by taking LCM.

We get: $ \frac{d - 44}{11} = - 13 $

$ \implies d - 44 = - 13 \times 11 = - 143 $

$ \implies d = - 143 + 44 $

$ \implies \textbf{d} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 99} $

Q7: 5t + 12 = 4t - 1

We club the like terms on either side.

$ \implies 5t - 4t = - 1 - 12 $

$ \implies (5 -4)t = - 13 $

$ \implies \textbf{t} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Hence, the answer.

7 0
3 years ago
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