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Svetllana [295]
3 years ago
13

JEEZUS PLEASE HELP ME PEOPLE KEEP TROLLING ME AND NONE OF MY ANSWERS HAVE BEEN CORECTLY ANSWERED, I WILL GIVE MONEY FOR FLIPS SA

KE IF YOU HELP!!!!

Mathematics
1 answer:
Savatey [412]3 years ago
8 0

Answer:

14. 6 x 10^{17}

15. 28.615 x 10^{10}

16. I'm so sorry, I'm not sure!

17. 1.26 x 10^{10}

18. 1.639 x 10^{-8}

19. 2.025 x 10^{17}

<em>Hope that helps! I'm sorry if it's wrong, and sorry about all the trouble that has been brought upon you!</em>

<em></em>

<em>-Aphrodite</em>

Step-by-step explanation:

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D....the empty weight is 160gr
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4 years ago
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During an experiment, Mrs. Melsoner uses an analytical scale to measure the mass of a substance. The analytical scale says she h
stich3 [128]

Answer:

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The correct answer is ( D )

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7 0
3 years ago
A video sharing website starts with 20,000 members. Each year it loses 25% of the members, but adds 10,000 new members after the
MrMuchimi
20,000 x 25 = 500,000
500,000 divided by 100 = 5,000 members are lost.
Members left = 15,000
Members added = 10,000
Members every year  = Members left + Members added
                                   =          15,000 +  10,000
                                   =          25,000

6 0
3 years ago
A rectangular board has a perimeter of 28 feet. if the length is twice the width minus 1 foot, then what is the length of the bo
Westkost [7]
P = 2(L + W)
P = 28 
L = 2W - 1

28 = 2(2W - 1 + W)
28 = 2(3W - 1)
28 = 6W - 2
28 + 2 = 6W
30 = 6W
30/6 = W
5 = W ....width is 5 ft

L = 2W - 1
L = 2(5) - 1
L = 10 - 1
L = 9 <=== length is 9 ft
4 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
3 years ago
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