Five less than 3 times the length, l

A warehouse employs 22 workers on first shift and 14 workers on second shift. Eight workers are chosen at random to be interview

lara [203]

36 all together.
22 first
14 second
8 random chosen

A) all first shift:
One is pulled 22/36
Second is pulled 21/35
Third is pulled 20/34
Fourth 19/33
Fifth 18/32
Sixth 17/31
Seventh 16/30
Eighth 15/29

Multiply all those together
Probability of all first shift is 0.010567296996663
(That means it's not happening anytime soon lol)

B) one worker 14/36
Second 13/35
Third 12/34
Fourth 11/33
Fifth 10/32
Sixth 9/31
Seventh 8/30
Eighth 7/29

Multiply all those together
Probability of all second shift is 0.000099238805645
(That means it's likely to see 100x more picks of all first shift workers before you see this once.. lol)

C) 22/36
21/35
20/34
19/33
18/32
17/31

Multiply..
Probability.. 0.038306451612903

D) 14/36
13/35
12/34
11/33

X... p=0.016993464052288

Probably not correct, haven't done probability in years.

8 0

2 years ago

Doug split a pack of cards so that he and his friends each got 6 cards. If there were 24 cards in the pack, how many friends did

GuDViN [60]

Answer:

3

Step-by-step explanation:

24 divided by 6 is 4, subtract Doug, there were 3 friends

4 0

2 years ago

A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears

arsen [322]

Answer:

The correct answer is "0.0000039110".

Step-by-step explanation:

The given values are:

$Y_n\rightarrow N(\mu, \sigma^2)$

$\mu = 40n$

$\sigma^2=100n$

$n=20$

then,

The required probability will be:

= $P(Y_{20}>1000)$

= $P(\frac{Y_{20}-\mu}{\sigma} >\frac{1000-40\times 20}{\sqrt{100\times 20} } )$

= $P(Z>\frac{1000-800}{44.7214} )$

= $P(Z>\frac{200}{44.7214} )$

= $P(Z>4.47)$

By using the table, we get

= $0.0000039110$

6 0

2 years ago

Perry spent $22.50 on material to make necklaces. He used all of the material and made 15 necklaces. How much should Perry charg

Vika [28.1K]

Answer:

Guys his answer is wrong. It’s 5.50 in edg

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

a company owns two dealerships, both of which sell cars and trucks. the first dealership sells a total of 164 cars and trucks. t

OLEGan [10]

Answer:

294 cars.

Step-by-step explanation:

Let x be the number of cars and y be the number of trucks.

We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:

$x+y=164...(1)$

The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.

Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:

$2x+\frac{y}{2}=229...(2)$