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Kamila [148]
3 years ago
11

Five less than 3 times the length, l

Mathematics
1 answer:
natita [175]3 years ago
3 0
The equation would be 3l-5.
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What percent is equivalent to 8/40 ? 8% 20% 25% 40%
Nikitich [7]
First you have to get the number on the right 40 to equal 100 so do 40x2=80- +40x1.5= 100

Then do the same thing to the first number 8 so 8x2=16+8x1.5=20

then you have 20/100 right so then that number over 100 is the percent that you get ^-^ 20%
7 0
3 years ago
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How is adding 0.267 to 50.9 different from adding 0.26 to 50.9
Brut [27]

Answer:

Step-by-step explanation:

They are different numbers:

0.269 + 50.9 = 51.169

0.26 + 50.9 = 51.16

8 0
3 years ago
Pythagorean Theorem??
IgorC [24]

Answer:

26

Step-by-step explanation:

5 0
3 years ago
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WHO CAN solve it Please !
Mariulka [41]

Answer:

a) True

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the definite integration</em>

<em>            </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha<em></em>

<em>we know that the trigonometric formula</em>

<em> sin²∝+cos²∝ = 1</em>

<em>            cos²∝ = 1-sin²∝</em>

<u><em>step(ii):-</em></u>

<em>Now the  integration</em>

<em>         </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha<em></em>

<em>                                      = </em>\int\limits^\pi _0 {cos\alpha } \, dx<em></em>

<em>Now, Integrating </em>

<em>                                  </em>= ( sin\alpha )_{0} ^{\pi }<em></em>

<em>                                = sin π - sin 0</em>

<em>                               = 0-0</em>

<em>                              = 0</em>

<u><em>Final answer:-</em></u>

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

<em></em>

<em></em>

5 0
3 years ago
What’s the value of x?
GaryK [48]

12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc12ewrgfbrfc

7 0
3 years ago
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