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3 years ago

Example of kinetic to potential ? And how the energy is changing forms???? Please help

Physics

1 answer:

faust18 [17]3 years ago

8 0

Answer:

A ball when from moving to stoping

Explanation:

Kinetic = energy of motion

Potential = energy stored

When you roll a ball on the ground, it gains kinetic energy, but then the ball starts to slow down until it stops and it remains at rest which means it's at potential energy. It went from moving (kinetic) to stoping (potential)

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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The speed of light is about 300,000 km/s (3×105km/s). If Jupiter is 0.72 light hours from the Sun, how far is this?

Daniel [21]

Answer:

7.77 x 10⁸ Km

Explanation:

given,

Speed of light = 3 x 10⁵ Km/s

= 3 x 10⁸ m/s

1 light hour = 1.079 x 10⁹ Km

now,

0.72 light hour = 0.72 x 1.079 x 10⁹ Km

= 0.7769 x 10⁹ Km

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The Jupiter is 7.77 x 10⁸ Km far from sun.

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4 years ago

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What happens whenever energy is transformed from one form to another?

andriy [413]

Answer:

Energy transformation is when energy changes from one form to another – like in a hydroelectric dam that transforms the kinetic energy of water into electrical energy. While energy can be transferred or transformed, the total amount of energy does not change – this is called energy conservation.

Explanation:

Hope This Helps!!

God Bless!!

~DuffyDuck~

3 0

3 years ago

What is the speed of a rocket that travels 9,000 meters in 12 seconds?

Mademuasel [1]

9,000/12=750

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3 years ago

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The acceleration of an object would increase if there was an increase in the

xxMikexx [17]

As per Newton's II law we know that

$F_{net} = ma$

here we know that

$F_{net} = F_{ap} - F_f$

so here we will have

$a = \frac{F_{ap} - F_f}{m}$

so here if we need to increase the acceleration we need to increase the applied force while on increasing the mass or on increasing the friction force the acceleration will decrease.

So here correct answer will be

<em>A) force on the object.</em>

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4 years ago

A stunt cyclist rides on the interior of a cylinder 13 m in radius. The coefficient of static friction between the tires and the

ZanzabumX [31]

Answer:

$v=13.1m/s$

Explanation:

From the question we are told that:

Radius r=13

Coefficient of static friction \mu=0.67

Given the Centripetal concept

Generally the equation for Velocity v is mathematically given by

$v=\sqrt{\frac{gr}{\mu}}$

$v=\sqrt{\frac{9.81*13}{0.67}}$

$v=13.1m/s$

The value of the minimum speed (in m/s) for the cyclist to perform the stunt is Given as

$v=13.1m/s$

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3 years ago