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3 years ago

Example of kinetic to potential ? And how the energy is changing forms???? Please help

Physics

1 answer:

faust18 [17]3 years ago

8 0

Answer:

A ball when from moving to stoping

Explanation:

Kinetic = energy of motion

Potential = energy stored

When you roll a ball on the ground, it gains kinetic energy, but then the ball starts to slow down until it stops and it remains at rest which means it's at potential energy. It went from moving (kinetic) to stoping (potential)

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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A stone of 1 kg is thrown with a velocity of 40 m/s across the frozen surface of a lake and comes to rest after travelling a dis

yawa3891 [41]

Answer:

C)-16 N

Explanation:

concepts used

force = mass* acceleration

equation of motion

$v^2 = u^2 + 2as$

where v is the final velocity

u is the initial velocity

and s is the distance moved

______________________________________________

Given

mass = 1 kg

initial velocity (u) = 40m/s

final velocity (v) = 0 as stones comes to rest

distance moved by stone (s) = 50m

using $v^2 = u^2 + 2as$

$0 = 40^2 +2a*50\\=> -1600 = 100a\\=> a = -1600/100 = -16$

Thus, acceleration is -16 m/s^2

here acceleration is negative as force of friction is opposing the motion.

Force of friction = mass of stone * acceleration of stone

Force of friction = 1*-16 kgm/s^2 = -16N ( kgm/s^2 = 1 N)

Thus, option c -16N is correct choice.

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3 years ago

The amplitude of a sound is the A. frequency of the sound. B. magnitude of displacement of a sound pressure wave. C. psychologic

AlladinOne [14]

Answer:

Option B. magnitude of displacement of a sound pressure wave

Explanation:

Amplitude is simply the maximum displacement of a wave from its mean position.

6 0

4 years ago

Read 2 more answers

What is the resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm2?

nadya68 [22]

The resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm² will be 0.74 ohm.

<h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

ρ is the resistivity of tungsten = 5.6×10⁻⁸ (ohm m)

The relation of resistance with length and thickness is given by ;

$\rm R= \frac{\rho L}{A} \\\\ \rm R= \frac{5.6 \times 10^{-8}\times 2}{0.15 \times 10^{-6}} \\\\ R=0.74 \ ohm$

Hence, the resistance of tungsten wire will be 0.74 ohm.

To learn more about the resistance, refer to the link;

brainly.com/question/20708652

#SPJ1

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2 years ago

Can someone help me with notes for an essay? Will give brainliest and repost for 100 pts if yes.

Tom [10]

Answer:

Here so tip for ur essay

Explanation:

the topic : Space Stations or The Age Of Space Exploratio

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3 years ago

A conical container of radius 6 ft and height 24 ft is filled to a height of 19 ft of a liquid weighing 64.4 lb divided by ft cu

kobusy [5.1K]

Answer:

Part (i) work required to pump the contents to the rim is 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5ft above the cone's rim is 426,484.878 lb.ft

Explanation:

The center of mass of a uniform solid right circular cone of height h lies on the axis of symmetry at a distance of h/4 from the base and 3h/4 from the top.

Center mass of the liquid Z = (24-19)ft + 19/4 = 5ft + 4.75ft = 9.75 ft

Mass of liquid in the cone = volume × density (ρ) = ¹/₃.π.r².h.ρ

where;

r is the radius of the liquid surface = [6*(19/24)]ft = 4.75ft

ρ is the density of liquid = 64.4 lb/ft³

h is the height of the liquid = 19 ft

Mass of liquid in the cone = ¹/₃ × π × (4.75)² × 19 × 64.4 = 28,914.229 lbs

Part (i) work required to pump the contents to the rim

Work required = 28,914.229 lbs × 9.75 ft = 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5 ft above the cone's rim

Extra work required = 28,914.229 lb × 5ft = 144571.145 lb.ft

Total work required = (281,913.733 + 144571.145) lb.ft

= 426,484.878 lb.ft

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3 years ago