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aleksandrvk [35]
4 years ago
7

The speed of light is about 300,000 km/s (3×105km/s). If Jupiter is 0.72 light hours from the Sun, how far is this?

Physics
2 answers:
Daniel [21]4 years ago
7 0

Answer:

7.77 x 10⁸ Km

Explanation:

given,

Speed of light = 3 x 10⁵ Km/s

                        = 3 x 10⁸ m/s

1 light hour = 1.079 x 10⁹ Km

now,

0.72 light hour = 0.72 x 1.079 x 10⁹ Km

                         = 0.7769 x 10⁹ Km

                         = 7.77 x 10⁸ Km

The Jupiter is 7.77 x 10⁸ Km far from sun.

frozen [14]4 years ago
7 0

Answer:

Explanation:

speed of light, v = 3 x 10^8 m/s

time = 0.72 hour

distance = velocity x time

distance = 3 x 10^8 x 0.72 x 3600

distance = 7776 x 10^8 m = 7.78 x 10^8 km

Thus, the distance is 7.78 x 10^8 km.

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A bullet with a mass 2.25g is fired up into the air with a velocity of 187.5 m/s. What is the maximum height of the bullet
Ksivusya [100]

Answer:

1793.7m

Explanation:

From the principle of conservation of energy; the kinetic energy substended by the object equals the potential energy sustain by the object when it gets to its maximum position.

Now the kinetic energy; is

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v is velocity

Hence.

K.E = 1/2 × 2.25 × (187.5)^2

Now this should be same with the potential energy which is given as;

P.E = m× g× h

Where m is mass of object

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h is maximum height substain by the object.

Hence P.E = 2.25 × 9.8 × h

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1/2 × 2.25 × (187.5)^2 =2.25 × 9.8 × h

=> 1/2 × (187.5)^2 = 9.8 × h

=>1/2 × (187.5)^2 / 9.8 = h

=> 1793.69m = h

h= 1793.69m

h =1793.7m to 1 decimal place

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