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3 years ago

The speed of light is about 300,000 km/s (3×105km/s). If Jupiter is 0.72 light hours from the Sun, how far is this?

Physics

2 answers:

Daniel [21]3 years ago

7 0

Answer:

7.77 x 10⁸ Km

Explanation:

given,

Speed of light = 3 x 10⁵ Km/s

= 3 x 10⁸ m/s

1 light hour = 1.079 x 10⁹ Km

now,

0.72 light hour = 0.72 x 1.079 x 10⁹ Km

= 0.7769 x 10⁹ Km

= 7.77 x 10⁸ Km

The Jupiter is 7.77 x 10⁸ Km far from sun.

frozen [14]3 years ago

7 0

Answer:

Explanation:

speed of light, v = 3 x 10^8 m/s

time = 0.72 hour

distance = velocity x time

distance = 3 x 10^8 x 0.72 x 3600

distance = 7776 x 10^8 m = 7.78 x 10^8 km

Thus, the distance is 7.78 x 10^8 km.

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Answer:

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Let the length required be 'L'.

Given:

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$\rho\times L=R\times A\\\\L=\frac{R\times A}{\rho}$

Now, plug in the given values and solve for length 'L'. This gives,

$L=\frac{3.7\ \Omega\times 1.13\times 10^{-5}\ m^2}{1.8\times 10^{-5}\ \Omega\cdot m}\\\\L=\frac{4.181}{1.8}=2.32\ m$

Therefore, the length of the material required to make a resistor of 3.7 Ω is 2.32 m.

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