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3 years ago

The speed of light is about 300,000 km/s (3×105km/s). If Jupiter is 0.72 light hours from the Sun, how far is this?

Physics

2 answers:

Daniel [21]3 years ago

7 0

Answer:

7.77 x 10⁸ Km

Explanation:

given,

Speed of light = 3 x 10⁵ Km/s

= 3 x 10⁸ m/s

1 light hour = 1.079 x 10⁹ Km

now,

0.72 light hour = 0.72 x 1.079 x 10⁹ Km

= 0.7769 x 10⁹ Km

= 7.77 x 10⁸ Km

The Jupiter is 7.77 x 10⁸ Km far from sun.

frozen [14]3 years ago

7 0

Answer:

Explanation:

speed of light, v = 3 x 10^8 m/s

time = 0.72 hour

distance = velocity x time

distance = 3 x 10^8 x 0.72 x 3600

distance = 7776 x 10^8 m = 7.78 x 10^8 km

Thus, the distance is 7.78 x 10^8 km.

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When would a scientist accept the alternative

vredina [299]

Answer:

B.) if statistical results are significant

Explanation:

If a scientist accepts the null hypothesis, then there is enough evidence to reject the null hypothesis.

This means that the p-value is less than the significance level.

When the scientist accepts the alternative hypothesis, it means the statistical results are significant.

The correct answer is B.

3 0

3 years ago

In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5

kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

Slits separation, $d=2.2\times 10^{-5}\ m$

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})$

$\theta=2.34^{\circ}$

Hence, this is the required solution.

4 0

3 years ago

A negative charge is moving across a room from south to north. A magnetic field runs from east to west. In what direction is the

erica [24]

Here is your answer

C. towards the floor

REASON:

Using Fleming's Left hand rule we can determine the direction of force applied on a moving charged particle placed in a magnetic field.

The direction of current will be just opposite to the direction of electron(negative charge) because current moves from positive to negative terminal whereas electron moves from negative to positive terminal.

So, direction of current- North to South

Now applying Fleming's Left hand rule we get the direction of force in downward direction, i.e. towards the floor.

HOPE IT IS USEFUL

6 0

3 years ago

Read 2 more answers

An experimentalist fires a beam of electrons, creating a visible path in the air that can be measured. The beam is fired along a

gtnhenbr [62]

Answer:

Velocity of the electron in the beam.

Radius of the circulating electrons due to the magnetic field.

Explanation:

We have a Mathematical expression for the force on a moving charge in a magnetic field as:

$F=q.v.B.sin \theta$ ...........................(1)

where:

q= charge on the particle in coulomb

v= velocity of the charge projected into the magnetic field

B= intensity of the magnetic field in tesla

$\theta$ = angle between the velocity and direction of magnetic field

For the forces on rotating mass we have the formula:

$F=m.\frac{v^2}{r}$ ..........................................(2)

where:

m= mass of the charged particle

v= velocity of projection of charge into the magnetic field

r= radius of the path traced by the charge in the magnetic field

From eq. (1) and (2) we can calculate the magnetic field .

Now,

Using Ampere's Law we have:

$B = \frac{\mu_0 .I}{2 \pi r}$

where:

I= current in the wire

$\mu_0=$ The permeability of free space.

r= radial distance from the current carrying wire( in this case it is same as the radius of the circular path)

4 0

3 years ago

As a consultant to the soft-drink industry, Dr. J is given the task of conducting the ultimate Pepsi taste test. This is Dr. J's

dem82 [27]

Answer:

A) How much work does the Pepsi do on the bullet = 0.0625J

B) At what velocity does the Pepsi hit the floor = 7.67m/s

Explanation:

Given mass of bullet = 5g

initial velocity = 500 m/sec

final velocity = 5 m/sec

From work done = Force X Distance

WD = Mad

a = v - u /t

Workdone ; m(v - u )/t

A) The work done by the Pepsi is equal to the change in kinetic energy while in the Pepsi:

but The work done by the container wall on the bullet is equal to the change in kinetic energy on either side of the wall: W = change in kinetic energy = 1/2 mv²

= 1/2 X 0.005 x 500² - 1/2 X 0.055 x 5²

= 624.94J

Therefore ; The work done by the Pepsi is equal to the change in kinetic energy while in the Pepsi = W = change in KE = 0.0625 - 0 = 0.0625J

B) At what velocity does the Pepsi hit the floor?

From conservation of energy principle; PE = KE

mgh = 1/2mv²

0.98 X 3 = 1/2v²

velocity = 7.67m/s

3 0

3 years ago