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harina [27]
3 years ago
13

Who is the president of kenya​

Physics
2 answers:
lesya [120]3 years ago
6 0
<h3>Question:</h3>

Who is the president of Kenya?

<h2>Answer:</h2>

Uhuru Kenyatta

dem82 [27]3 years ago
3 0

Answer:

Uhuru Muigai Kenyatta

Explanation:

He was born on 26 October 1961.

He is a Kenyan politician, businessman, and the fourth and current President of the Republic of Kenya.

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If a black hole itself emits no radiation, what evidence do astronomers and physicists today have that the theory of black holes
AleksandrR [38]

Answer:

Einstein's general theory of relativity is the theory behind black holes has been tested with a wide range of experiments of which all confirm the predictions the theory makes. We cannot see black holes phenomena inside the event horizon, we do observe things outside this limit.

Black holes in binary star systems leave signs of their presence on neighboring star thats detected and the signs include X-ray emissions, accretion disks, and large orbit perturbations.

this is the evidence that astronomers and physicists have to show that the theory about black holes is correct.

6 0
3 years ago
1150 g - 0.652 kg = ______________g?
beks73 [17]
Answer is 498 grams
6 0
3 years ago
Read 2 more answers
Calculate the accleration of a car if its velocity increases from 15m/s to 75m/s in 5 second​
andrezito [222]

Answer:

I think the acceleration is 12m/s

3 0
3 years ago
(a) What is the escape speed on a spherical asteroid whose radius is 545 km and whose gravitational acceleration at the surface
Keith_Richards [23]

Answer:

1777.92 m/s

Explanation:

R = Radius of asteroid = 545 km

M = Mass of planet

g = Acceleration due to gravity = 2.9 m/s²

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Acceleration due to gravity is given by

g=\dfrac{GM}{R^2}\\\Rightarrow M=\dfrac{gR^2}{G}

The expression of escape velocity is given by

v=\sqrt{\dfrac{2GM}{R}}\\\Rightarrow v=\sqrt{\dfrac{2G}{R}\dfrac{gR^2}{G}}\\\Rightarrow v=\sqrt{2gR}\\\Rightarrow v=\sqrt{2\times 2.9\times 545000}\\\Rightarrow v=1777.92\ m/s

The escape speed is 1777.92 m/s

3 0
3 years ago
Read 2 more answers
The distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this
antiseptic1488 [7]

Answer:

<h3>14.97m/s</h3>

Explanation:

Given

Initial velocity of the car u = 8m/s

Distance travelled by the rider S = 40m

Acceleration a = 2m/s²

Required

rider's velocity after the acceleration v

Using the equation of motion

v² = u²+2as

v² = 8²+2(2)(40)

v² = 64+160

v² = 224

v = √224

v = 14.97m/s

Hence the rider's velocity after the acceleration is 14.97m/s

5 0
3 years ago
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