The Hertzsprung- Russel diagram is used to how the relationship between the absolute magnitudes of stars and their effective temperatures.
Alot? You didn’t show me any work to solve
1j=1newton*meter
force=mass*accel
200N=55x
200/55=3.636......
3.636...-2=1.636.....
1.636 is the deceleration resulting from friction hence the force of friction is 1.636*55=90newtons
90newtons*distance of 10 meters= 900 j of work done by friction
Answer:
Here, m=10 kg
The resultant force acting on the body is
F=(98N)2+(6N)2=10N
Let the resultant force F makes an angle θ w.r.t. 8N force.
From figure, tanθ=8N6N=43
The resultant acceleration of the body is
a=mF=10kg10N=1ms−2
The resulatnt acceleration is along the direction of the resulatnt force.
Hence, the resultant acceleration of the body is 1 ms−2 at an angle of tan−1(43) w.r.t. 8N force.

Answer:
I = 4.38 x 10⁻⁷ A
Explanation:
Given,
speed = 4.47 x 10⁴ m/s
radius of the circular path, r = 2.59 x 10⁻⁹ m
effective current = ?
The current represented by the orbiting electron is equal to
f is the frequency
q is charge of electron
we know,
f = 2.74 x 10¹² Hz
now,
I = 4.38 x 10⁻⁷ A
Hence, the effective current associated with the orbiting electron is equal to I = 4.38 x 10⁻⁷ A
