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ASHA 777 [7]
4 years ago
15

The acceleration of an object would increase if there was an increase in the

Physics
1 answer:
xxMikexx [17]4 years ago
4 0

As per Newton's II law we know that

F_{net} = ma

here we know that

F_{net} = F_{ap} - F_f

so here we will have

a = \frac{F_{ap} - F_f}{m}

so here if we need to increase the acceleration we need to increase the applied force while on increasing the mass or on increasing the friction force the acceleration will decrease.

So here correct answer will be

<em>A) force on the object.</em>

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Which pm the following are likely to form a covalent bond
Alecsey [184]

Answer:

magneisuim and gold

Explanation:

8 0
4 years ago
Read 2 more answers
During a 40-mile trip, Marla traveled at an average speed of x miles per hour for the first y miles of the trip and at an averag
Ilya [14]

Answer:

\dfrac{32+0.2y}{40}

Explanation:

Total =40 miles.

y miles at x miles/hr.

40- y miles at 1.25 x miles/hr.\

We know that

Distance = time x velocity

For y miles

Lets time taken to cover y miles is t

y = x t

t=y/x                -----------1

For 40- y

Lets time taken to cover 40- y is t'

40- y = 1.25 x t'  

t'=(40-y)/1.25x           -----------2

By adding both equation

t+t'=y/x  + (40-y)/1.25x

t+t'=(32+0.2y)/x

Now lets time T taken by Marla if she will travel at x miles per hr for entire trip.

40 = x T

T=40/x

So

\dfrac{t+t'}{T}=\dfrac{32+0.2y}{40}

To find numerical value of above expression we have to know the value of y.

8 0
4 years ago
If an object is tossed up into the air, what is its velocity at the top of the object's path? (Units are ms-1)
Novay_Z [31]

Answer: 0\ ms^{-1}

Explanation:

Given

If an object reaches the topmost point i.e. it cannot travel beyond that point as its velocity is zero at the topmost point

As some velocity is needed to move the object, so velocity at topmost point is zero

7 0
3 years ago
A 76g ball is attached to a string that is 1.5m long. It is spun so that it completes two full rotations every second. What is t
Marat540 [252]

The centripetal acceleration = 236.63 m/s²

The force = 17.98 N

<h3>Further explanation</h3>

Given

mass = 76 g = 0.076 kg

r = 1.5 m

f = 2 rps = 2 rotation per second

Required

The centripetal acceleration

The Force tension

Solution

Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle  

\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}

F = centripetal force, N  

m = mass, Kg  

v = linear velocity, m / s  

r = radius, m  

The speed that is in the direction of the circle is called linear velocity  

Can be formulated:  

\tt \displaysyle v = 2 \pi.r.f

r = circle radius  

f = rotation per second (RPS)  

The linear velocity : 2 x 3.14 x 1.5 x 2 =18.84 m/s

The centripetal acceleration : ac = v²/R = 236.63 m/s²

The force : F = m x ac = 0.076 x 236.63 = 17.98 N

4 0
3 years ago
Consider a substance that has high heat capacity. As compared to a substance with low heat capacity, when an equal amount of hea
Nesterboy [21]

Answer: will be raised through lower temperature change(lower ∆T) when compared to the low heat capacity substance.

Explanation:

Heat capacity is the amount of heat needed to raise the temperature of a substance through 1°C(1 unit temperature).

Therefore the high heat capacity substance will require more heat to raise it through 1 unit temperature when compared to the low heat capacity substance. So when the same amount of heat is added to the two substance the high heat capacity substance is raised through lower temperature change when compared to the low heat capacity substance.

8 0
3 years ago
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