Answer: 20x4−24x3+20x2
Step-by-step explanation:
when simplifying you first distribute the -4x^2. This will result in -24x^3, 20x^4, and 20x^2
Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
Answer:
A,C
Step-by-step explanation:
i took the test
Answer:
6
Step-by-step explanation:
x=6
ax+bx=cx
10+bx=16
10+6=16
x=6
Answer:
x= 0.4
Step-by-step explanation:
We need to solve and find the value of x
7 1/3x = 1.6 ÷ 6/11
Converting mixed fraction into improper fraction
22/3 x = 1.6 ÷ 6/11
Converting ÷ sign by X and reciprocating the term
22/3 x = 1.6 * 11/6
Now divide both sides by 3/22
x = 1.6 * 11/6 * 3/22
x = 1.6 * 1/2 * 1/2
x = 1.6/4
x = 0.4
S0, x= 0.4
