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2 years ago

What expression is eqivalent to 1/27

Mathematics

2 answers:

Zepler [3.9K]2 years ago

7 0

Answer:

3^4 x 3^-7

Step-by-step explanation:

liraira [26]2 years ago

5 0

It’s 3 ^ 4 x 3 ^ - 7

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115. Sami opens an account and deposits $100 into it at the end of each month. The account earns 2% per year compounded monthly.

givi [52]

Step-by-step explanation:

Geometric series.

Month 3.

100(1+\frac{0.02}{12})^2 + 100(1+\frac{0.02}{12})+100

Month 4.

100( 1 + \frac{0.02}{12})^3 + 100( 1 + \frac{0.02}{12})^2+100(1+\frac{0.02}{12})+100

Month 5.

100(1 + \frac{0.02}{12})^4 + 100(1 + \frac{0.02}{12})^3 + 100(1 + \frac{0.02}{12})^2 +100( 1 + \frac{0.02}{12}) + 100

4 0

3 years ago

In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform

Semmy [17]

Answer:

95% Confidence interval: (0.0429,0.0791)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

$\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96$

Putting the values, we get:

$0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)$

is the required confidence interval for proportion of all new websites that were anonymous.

8 0

2 years ago

P = nc - e and p is 4520 and n is 3000 and e is 700 what is the value of c

adoni [48]

Answer:

c= 1.74

Step-by-step explanation:

4520 = 3000(c)-700

4520=3000c-700

+700 +700

5220=3000c

c=1.74

to check to see if this is right you would do this:

4520=3000(1.74)-700

4520=5220-700

4520=4520

3 0

3 years ago

Write 1-2log7x as a single logarithm

slavikrds [6]

Answer:

$log_{7} \frac{7}{x^{2} }$

Step-by-step explanation:

We need to write $1 - 2log_{7}x$ as a single logarithm.

We know that

$log_{7}7 = 1$

Therefore we have:

$log_{7}7 - 2log_{7}x$

→ $log_{7}7 - log_{7}x^{2}$

→ $log_{7} \frac{7}{x^{2} }$

The solution is: $log_{7} \frac{7}{x^{2} }$

4 0

3 years ago

Kim sells flowers in 25 pound crates to the flower mart if she sells 100 crates how many pounds of flowers does she sell

Kisachek [45]

25*100

2500 lbs of flowers will be sold

8 0

3 years ago

What expression is eqivalent to 1/27​

What expression is eqivalent to 1/27