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myrzilka [38]
3 years ago
7

0.023ml= blank cl PLEASE HELP

Chemistry
1 answer:
Rus_ich [418]3 years ago
6 0
0.23cL because 0.023mL= 23.0L so 23.0L= 0.23cL
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The gauge pressure inside a vessel is ‐40kPa, at an elevation of 5000m. a) What is the absolute pressure? b) At this elevation,
hoa [83]

Answer:

a) Pabs = 48960 KPa

b) T = 433.332 °C

Explanation:

  • Pabs = Pgauge + d*g* h

∴ d = 1000 Kg/m³

∴ g = 9.8 m/s²

∴ h = 5000 m

∴ P gauge = - 40 KPa * ( 1000 Pa / KPa ) = - 40000 Pa; Pa≡Kg/m*s²

⇒ Pabs = - 40000 Kg/ms² + ( 1000 Kg/m³ * 9.8 m/s² * 5000 m )

⇒ Pabs = 48960000 Pa = 48960 KPa

a) at that height and pressure, we find the temperature at which the water boils by means of an almost-exponential graph which has the following equation:

P(T) = 0.61094 exp ( 17.625*T / ( T + 243.04 ))......P (KPa) ∧ T (°C)....from literature

∴ P = 48960 KPa

⇒ ( 48960 KPa / 0.61094 ) = exp ( 17.625T / (T+ 243.04))

⇒ 80138.803 = exp ( 17.625T / ( T + 243.04))

⇒ Ln ( 80138.803) = 17.625T / ( T + 243.04))

⇒ 11.292 * ( T + 243.04 ) = 17.625T

⇒ 11.292T + 2744.289 = 17.625T

⇒ 2744.289 = 17.625T - 11.292T

⇒ 2744.289 = 6.333T

⇒ T = 433.332 °C

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Perform an online search to find the structures of the compounds in the questions that follow. Provide a method for separating t
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The chemical separation method for two of the above named mixtures or compound indicated above are explained below.

<h3>What is a Chemical compound?</h3>

A chemical compound is a material generated by the chemical union of two or more elements in set quantities.

<h3>What are the separation methods?</h3>

<u>Benzophenone and tributylamine</u>

The combination of benzophenone and tributylamine is in diethyl ether (given in question). Tributylamine is a base that may readily be changed to a water soluble salt by adding an aqueous acid.

Add dilute aqueous acid to the solution. The amine salt will be present in the aqueous layer, whereas benzophenone will be present in the ether layer. A separatory funnel will isolate levels.

<u>Fluorenone, octanoic acid, and dicyclohexylamine</u>

Fluorenone, Octanoic acid, and dicyclohexyl amine: The combination comprises both an acid (octanoic acid) and a base (dicyclohexyl amine) (dicyclohexyl amine).

Add the diluted aqueous base to the solution (like NaCO3). Divide the two layers.

The acid is present in the aqueous layer as a salt, while the fluorenone and amine are present in the ether layer.

Add weak aqueous acid to this combination of fluorenone and dicyclohexyl amine.

Divide the two layers. The amine is present in the aqueous layer, and fluorenone is present in the ether.

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2 years ago
Calculate the ph at the equivalence point for the titration of 0.230 m methylamine (ch3nh2) with 0.230 m hcl. the kb of methylam
Vlad1618 [11]

Answer: The pH at the equivalence point for the titration will be 0.65.

Solution:

Let the concentration of [OH^-] be x

Initial concentration of [CH3NH_2], c = 0.230 M

        CH_3NH_2+H_2O\rightleftharpoons CH_3NH_3^++OH^-

at eq'm  c-x                         x                    x

Expression of K_b:

K_b=\frac{[CH_3NH_3^+][+OH^-]}{[CH_3NH_2]}=\frac{x\times x}{c-x}=\frac{x^2}{c-x}

Since ,methyl-amine is a weak base,c>>x so c-x\approx c.

K_b=\frac{x^2}{c}=5.0\times 10^{-4}=\frac{x^2}{0.230 M}

Solving for x, we get:

x=1.07\times 10^{-2} M

Given, HCl with 0.230 M , it dissociates fully in water which means [H^+] = 0.230 M

[OH^-]=[H^+] will result in neutral solution, since [OH^-]

Remaining [H^+] after neutralizing [OH^-]ions

[H^+]_{\text{left in solution}}=[H^+]-[OH^-]=0.230-1.07\times 10^{-2}=0.2193 M

pH=-log{[H^+]_{\text{left in solution}}=-log(0.2193)=0.65

The pH at the equivalence point for the titration will be 0.65.

8 0
3 years ago
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