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3 years ago

11

A school charges $6 for admission to a football game. The school has already sold 129 tickets x must be sold to earn at least $9

00? Write you answer as an inequality.

1 answer:

docker41 [41]3 years ago

5 0

Answer:

150

Step-by-step explanation:

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1.7cubic feet per minutes Given that one cubic foot is equivalent to approximately 7.48 gallons what would the pump rating be in

son4ous [18]

Answer:

449 per hour

Step-by-step explanation:

First of all we know the question is asking us to round to the nearest tenth and find the rate of gallons per hour.

First:

Know there are 60 minutes in one hour

Second:

Take 7.48 and multiply it by 60

Third:

This should give you---448.8

Which is correct, but we are not done

Fourth:

Round to the nearest whole number

448.8

8 is closer to 10 than it is to 1 so we add 0.2

Which gives us 449

Five:

Just add the "per hour"

Six:

Your answer is---449 per hour---

7 0

4 years ago

Rotate the axes to eliminate the xy-term in the equation. Then write the equation in standard form.

kirill115 [55]

Answer:

$\dfrac{x'^2}{2}-\dfrac{y'^2}{2}=1$

Step-by-step explanation:

The rotation by angle $\theta$ formulas are

$\left\{\begin{array}{l}x=x'\cos \theta-y'\sin \theta\\y=x'\sin \theta+y' \cos \theta\end{array} \right.$

To eliminate the xy-term, we have to rotate by 45°, so

$\left\{\begin{array}{l}x=x'\cos 45^{\circ}-y'\sin 45^{\circ}\\y=x'\sin 45^{\circ} +y' \cos 45^{\circ}\end{array} \right.$

$\left\{\begin{array}{l}x=x'\dfrac{\sqrt{2}}{2}-y'\dfrac{\sqrt{2}}{2}\\y=x'\dfrac{\sqrt{2}}{2} +y' \dfrac{\sqrt{2}}{2}\end{array} \right.$

Substitute them into the equation $xy+1=0:$

$\left(x'\dfrac{\sqrt{2}}{2}-y'\dfrac{\sqrt{2}}{2}\right)\cdot \left(x'\dfrac{\sqrt{2}}{2}+y'\dfrac{\sqrt{2}}{2}\right)+1=0\\ \\\left(x'\dfrac{\sqrt{2}}{2}\right)^2 -\left(y'\dfrac{\sqrt{2}}{2}\right)^2+1=0\\ \\\dfrac{x'^2}{2}-\dfrac{y'^2}{2}=1$

8 0

3 years ago

one summer conservation officials caught and tagged 98 beavers in a rivers flood plain. later, 50 beavers were caught and 32 had

anyanavicka [17]

About 170 beavers are in the population

8 0

3 years ago

Help plz:)))I’ll mark u Brainliest

kirza4 [7]

Answer:

$sin^{-1}(\frac{51}{53})\\=74.21\\$

≈74

6 0

3 years ago

Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

OleMash [197]

Answer:

For every 5 students scoring in the 60s, there were 2 students scoring in the 70s.

Step-by-step explanation:

There are 40 scorers in the 60s and 16 scorers in the 70s. These are ratios, so the ratio between the 60s and the 70s would be 40/16. This fraction can be simplified down to 5/2. This means that for every 5 students scoring in the 60s, 2 scored in the 70s.

8 0

2 years ago