In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.
Now that we know the vertices of the surface
, we can parameterize it by
where
and
. The surface element is
With respect to our parameterization, we have
, so the surface integral is
I’m going with none because it would just be N-W= blank. Is the blank n or w. I mean it could be one of those but I don’t think you know enough about the question for it to be N or W. So I would say none. Sorry if I’m wrong.
Answer:
3b²(4b²+1)
Step-by-step explanation:
You can factor out a 3b²
3b²(4b²+1)
The reflection over the x-axis is given by the transformation:
f₁(x) = - f(x)
Therefore, the first step is:
f₁(x) = - log(4x)
Stretching by a factor n along the y-axis is given by the transformation:
f₂(x) = n · f₁(x)
Therefore we get:
f₂(x) = -3 · log(4x)
Shifting a function down of a quantity n is given by:
f₃(x) = f₂(x) - n
Therefore:
f₃(x) = -3·log(4x) - 2
Hence, the correct answer is C) g(x) = <span>-3·log(4x) - 2</span>