Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
105.8
EXPLANATION
15% de 92 es 13.8
92 + 13.8 = 105.8
Yes. 6/16 simplifies to 3/8, which is the same amount of people singing.
Answer:
Given that:
=2^(-4/5)
This means that 2 is the base and -4/5 is the exponent.
To change it in radical form:
- firstly the denominator would be written with radical sign
- Then the negative sign with 4 will be removed by inverting the base.
- Then the fraction will be simplified according to the exponent (power)
- All the steps are performed below:
![=\sqrt[5]{2^{-4} } \\=\sqrt[5]{1/2^4}\\ =\sqrt[5]{1/16}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B5%5D%7B2%5E%7B-4%7D%20%7D%20%5C%5C%3D%5Csqrt%5B5%5D%7B1%2F2%5E4%7D%5C%5C%20%3D%5Csqrt%5B5%5D%7B1%2F16%7D)
i hope it will help you!
