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3 years ago

11

Please help thank you..

1 answer:

Vlada [557]3 years ago

8 0

Answer:

Step-by-step explanation:

option d

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Can u help me pleaseee

snow_lady [41]

Answer:

x = 4

y = 2

Step-by-step explanation:

here's your explanation in attached picture

<h3>another question :</h3>

x = 5

y = 3

solution in attached picture

3 0

3 years ago

A 76 foot piece of rope is cut into three pieces where one piece is three times longer than the other two equal pieces. How long

jonny [76]

Let the length of one of the shorter pieces be $\ell$ . Then, we know that two of the pieces are that length, and the third piece is $3 \ell$ . Since these are all pieces of a rope, all we need to do to figure out the lengths is add all those together, solve for $\ell$ , and then plug that back in to the desired lengths:

$3 \ell + \ell + \ell = 76 ft.$
$5 \ell = 76 ft.$
$\ell = 15.2 ft.$

Shorter pieces: $\ell = \bf 15.2 ft.$
Longer piece: $3 \ell = \bf 45.6 ft.$

4 0

3 years ago

F(x)=x^2-3x+18 how many distinct real number zeros does f have?

vampirchik [111]

Answer:

None of the distinct real number zeros the function have.

Step-by-step explanation:

Considering the function

$f(x)=x^2-3x+18$

The zeroes of a function are those values that touches the x-axis. In order to find those values we must

Set $f(x) = 0$ in order to find those values

$0=x^2-3x+18$

$\mathrm{Switch\:sides}$

$x^2-3x+18=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-3,\:c=18:\quad x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}$

$x=\frac{-\left(-3\right)+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}$

$x=\frac{3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}$

As

$3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}=3+\sqrt{63}i$

so

$x=\frac{3+\sqrt{63}i}{2\cdot \:1}$

$x=\frac{3+3\sqrt{7}i}{2}$

$x=\frac{3}{2}+\frac{3\sqrt{7}}{2}i$

Similarly,

$x=\frac{-\left(-3\right)-\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}:\quad \frac{3}{2}-i\frac{3\sqrt{7}}{2}$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{3}{2}+i\frac{3\sqrt{7}}{2},\:x=\frac{3}{2}-i\frac{3\sqrt{7}}{2}$

BUT, NONE OF THEM ARE REAL NUMBER ZEROS.

Therefore, none of the distinct real number zeros the function have.

5 0

4 years ago

(u-2)(u+6)<br> Simplify your answer.

ratelena [41]

Answer:

u^2+4u-12

Step-by-step explanation:

u x u + 6u -2u - 2 x 6

4 0

3 years ago

Read 2 more answers

Find the area of the figure shown below and type your result in the empty box.<br><br><br>

lianna [129]

Answer:

did u forget to add the actual question

Step-by-step explanation:

5 0

3 years ago