What is the distance between -36 and -4 on a number line?

A sand dune stands 5 feet above sea level. The hill is eroding at a rate of 1 foot per 20 years. Let y represent the height of t

avanturin [10]

y = -1/2x + 5 should be your equation because it is 5 ft above sea level and its eroding, or going down, 1 ft per 20 years. So every year, the sand dune erodes 1/20 ft more.

Hope this helps!

4 0

3 years ago

Read 2 more answers

Identify the vertical asymptotes of f(x)=10/x^2-1

Brums [2.3K]

Answer:

-1 and 1

Step-by-step explanation:

5 0

2 years ago

A poll of 1068 adult Americans reveals that 48% of the voters surveyed prefer the Democratic candidate for the presidency. At a

zubka84 [21]

Answer:

Z = -1.333

P-value = 0.09176

Decision Rule: Reject $H_o$ if ∝ is greater than the P-value

Conclusion: Since P-value is > the level of significance ∝, we fail to reject the null hypothesis, therefore there is insufficient evidence to conclude that at least half of all voters prefer the Democrat.

Step-by-step explanation:

Given that:

The sample size of the poll = 1068

The proportion of voters that preferred Democratic candidate is $\hat p$ = 0.48

To test the claim that at least half of all voters prefer the Democrat, i.e 1/2 = 0.5

The null hypothesis and the alternative hypothesis can be computed as:

$H_o : p \geq 0.50$

$H_1 : p < 0.50$

Using the Z test statistics which can be expressed by the formula:

$Z = \dfrac{\hat p - p}{\dfrac{\sqrt{p(1-p) }}{n}}}$

$Z = \dfrac{0.48 - 0.5}{\dfrac{\sqrt{0.5(1-0.5) }}{1068}}}$

$Z = \dfrac{-0.02}{\sqrt{\dfrac{{0.5(0.5) }}{1068}}}$

$Z = \dfrac{-0.02}{\sqrt{\dfrac{{0.25}}{1068}}}$

$Z = \dfrac{-0.02}{0.015}$

Z = -1.333

P-value = P(Z< -1.33)

From z tables,

P-value = 0.09176

The level of significance ∝ = 0.05

Decision Rule: Reject $H_o$ if ∝ is greater than the P-value

Conclusion: Since P-value is > the level of significance ∝, we fail to reject the null hypothesis, therefore there is insufficient evidence to conclude that at least half of all voters prefer the Democrat.

5 0

2 years ago

A certain insecticide kills 60% of all insects in laboratory experiments. A sample of 12 insects is exposed to the insecticide i

Vilka [71]

Answer:

The probability that exactly 10 insects will die

P( X = 10 ) = 0.06385

Step-by-step explanation:

Step(i):-

Given a certain insecticide kills 60% of all insects in laboratory experiments

Given proportion p = 0.60

q = 1 - 0.60 = 0.40

Given sample size 'n' = 12

Step(ii):-

Let "X' be the random variable of binomial distribution

$P(X=r) = n_{C_{r} } p^{r} q^{n-r}$

The probability that exactly 10 insects will die

$P(X=10) = 12_{C_{10} } (0.60)^{10} (0.40)^{12-10}$

$n_{C_{r} } = \frac{n!}{(n-r)!r!} = \frac{12!}{(12-10)!10!} = 66$

$P(X=10) = 66 X (0.60)^{10} (0.40)^{2} = 0.06385$

Final answer:-

The probability that exactly 10 insects will die

P( X = 10 ) = 0.06385

4 0

3 years ago

Guys pls kindly help me with this one I will brainlest the one with a serious answer please I need it right now this is rush ple

Galina-37 [17]

Hey there :)

An exact answer cannot be given as it requires to reseach about banks and co-operatives in your locality. However, I can give you a hint.

Research banks or cooperatives in your location that has the greatest percentage in terms of investment or savings.

Let's say, for example, Bank ABC has 5% annual simple interest in their Savings Account.

If you invest your entire money 100,000 pesos at Bank ABC with 5% annual interest for 20 years, you will earn an interest of:

$Interest = Principal \times Rate \times Time$

$= > Interest =100000 \times 0.05 \times 20yrs$

$= > Interest = 100000$

Hence, after investing at Bank ABC for 20 years, you will earn 100,000 pesos on top of your principal/invested amount that is 100,000 pesos. Your money will become 200,000 pesos now.

So, with this, find a bank/cooperative that has the highest return rate in your location. Once you have decided bank/cooperative, research further with regards to the background of the company, other services offered, application requirements, etc.

~ Benjemin360

4 0

2 years ago