Check the picture below.
so the shape is really 4 triangles with a base of 2 and a height of 4 each, and 2 squares tha are 4x4.
![\bf \stackrel{\textit{area of the 4 triangles}}{4\left[\cfrac{1}{2}(2)(4) \right]}~~+~~\stackrel{\textit{area of the two squares}}{2(4\cdot 4)}\implies 16+32\implies 48](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%204%20triangles%7D%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%282%29%284%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20two%20squares%7D%7D%7B2%284%5Ccdot%204%29%7D%5Cimplies%2016%2B32%5Cimplies%2048)
Answer:
28
Step-by-step explanation:
To find the area of the shaded region, you have to start off with the area of the whole triangle. To find that, you multiply the height and length. length=10 height=8 (10x8=80). Then, since it's a triangle, you have to divide it by two (80/2=40). So, 40 is the area of the whole triangle. Then, you find the area of the white region, which is 12 (3x4=12). Finally, you take the area of the white square and subtract it from the area of the whole triangle (80-12=28). You would get 28.
Answer:
<em>Part A </em>C = (10,5)<em> Part B </em>C. D'(0,10)
Step-by-step explanation:
<em>Part A</em>
Since c is at the point (2,1) in relation to the origin, we can multiply those distances by our scale factor of 5
(2,1) * 5 = (10,5)
The new point C is going to be (10,5)
<em>Part B</em>
If you dilate with a factor of 5 -- relative to the origin -- you have to multiply the distance from <em>the origin</em> by 5.
In this case, point D is already on the y axis, so it's x value wouldn't be affected. Point D is currently 2 units away from (0,0), so we can multiply 2*5 to get 10 -- our ending point is (0,10)
Answer:
The correct option is the last one.
Step-by-step explanation:
To transform the graph of 
into 
the following steps are fulfilled:
1) Move the graph 2 units to the right:
Let 
then 
Notice that the cut point has been moved to x = 2.
2) Reflect on the x axis:
To reflect a graph on the x-axis we do 
Then 
3) Stretch according to factor 2.
For this we do 
Then we have 
4) Move up the graph in two units:
We do 
Then 
These steps coincide with those listed in the last option. Therefore the correct option is the last one.
"Translate 2 units on the right, reflect on the x-axis, stretch according to the factor 2 and translate 2 units"
