The volume of the stock solution needed is 213.88 mL to get new concentration.
<h3>What is molarity?</h3>
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.
Determination of the volume of stock solution.
Volume of diluted solution (V₂) =550 mL
Molarity of diluted solution (M₂) =0.70 M
Molarity of stock solution (M₁) = 1.8 M
Volume of stock solution needed (V₁) =?
M₁V₁ = M₂V₂
1.8 M × V₁ = 0.70 M × 550 mL
V₁ = 213.88 mL
Thus, the volume of the stock solution needed is 213.88 mL.
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Answer:
Theoretical yield of vanadium = 1.6 moles
Explanation:
Moles of 
= 1.0 moles
Moles of 
= 4.0 moles
According to the given reaction:-
1 mole of react with 5 moles of
Moles of Ca available = 4.0 moles
Limiting reagent is the one which is present in small amount. Thus, Ca is limiting reagent. (4.0 < 5)
The formation of the product is governed by the limiting reagent. So,
5 moles of Ca on reaction forms 2 moles of V
1 mole of Ca on reaction for 2/5 mole of V
4.0 mole of Ca on reaction for 
mole of V
Moles of V = 1.6 moles
<u>Theoretical yield of vanadium = 1.6 moles</u>
Answer:
Volcanologists use many different kinds of tools including instruments that detect and record earthquakes (seismometers and seimographs), instruments that measure ground deformation (EDM, Leveling, GPS, tilt), instruments that detect and measure volcanic gases (COSPEC), instruments that determine how much lava is moving underground (VLF, EM-31), video and still cameras, infrared cameras, satellite imagers, webcams, etc!
Explanation:
I HOPE IT HELPED
At diverging plate boundaries, earthquakes occurs as the plates pull away from each other. Volcanoes form between the plates, as magma rises upward from the underlying mantle. Second, two plates may come together, at a converging plate boundary. Two situations are possible at converging plate boundaries.
The relative molecular mass of acid A : 50 g/mol
<h3>Further explanation</h3>
Given
40.0 cm³(40 ml) of 0.2M sodium hydroxide
0.2g of a dibasic acid
Required
the relative molecular mass of acid A
Solution
Titration formula
M₁V₁n₁=M₂V₂n₂
n=acid/base valence(number of H⁺/OH⁻)
NaOH ⇒ n = 1
Dibasic acid = diprotic acid (such as H₂SO₄)⇒ n = 2
mol = M x V
Input the value in the formula :(1 = NaOH, 2=dibasic acid)
0.2 x 40 x 1 = M₂ x V₂ x 2
M₂ x V₂ = 4 mlmol = 4.10⁻³ mol ⇒ mol of Acid A
The relative molecular mass of acid A (M) :
