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valentinak56 [21]

3 years ago

8

WILL MARK BRAINLIEST- what is the lewis dot structure of CH2OH and N2O4

1 answer:

astra-53 [7]3 years ago

8 0

I'm not sure how to explain it on here without being able to draw but basically for every valence neutron you put 1 dot on each side of the element symbol like and once you go all the way around you start adding 2 dots and the maximum you can have is 2 dots on each side, hope this helped

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Which of the following is not true about compounds?

finlep [7]

Answer:

Elements can combine in any proportion to form a compound. -third choice

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3 years ago

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Provide the atomic mass an ion contains 16 protons,17 neutrons and 18 electrons

Rasek [7]

Answer:

37

Explanation:

Atomic mass is the sum of protons and neutrons in an atom.

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3 years ago

The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan

Alex17521 [72]

Answer : The rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $701K$ = $2.57M^{-1}s^{-1}$

$K_2$ = rate constant at $525K$ = ?

$Ea$ = activation energy for the reaction = $1.5\times 10^2kJ/mol=1.5\times 10^5J/mol$

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 701 K

$T_2$ = final temperature = 525 K

Now put all the given values in this formula, we get:

$\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]$

$K_2=0.0606M^{-1}s^{-1}$

Therefore, the rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

8 0

3 years ago

A source of zinc metal can be zinc ore containing zinc(II) sulfide. The ore is roasted in pure oxygen to produce the oxide and t

morpeh [17]

Answer:

32.7 grams of Zn will remained in the crucible after cooling.

Explanation:

$2ZnS+3O_2 \rightarrow 2ZnO + 2SO_2$ ..[1]

$ZnO+C\rightarrow Zn+CO$ ..[2]

Adding [1] + 2 × [2] we get:

$2ZnS+3O_2+2C \rightarrow 2Zn + 2CO+2SO_2$ ..[3]

Moles of ZnS in crucible = 0.50 mol

According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.

Then 0.50 moles of ZnS will give:

$\frac{2}{2}\times 0.50 mol=0.50 mol$ of Zn.

Mass of 0.50 moles of Zn =

= 0.50 mol × 65.4 g/mol =32.7 g

32.7 grams of Zn will remained in the crucible after cooling.

5 0

3 years ago

Which is the formula mass of (NH4)2SO4

Kobotan [32]

The formula mass is 132.14 g/mol

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