Question

How many atoms of Kr (Krypton) are in a balloon that contains 2.00 mol of Kr? (4)

Answer 1

Answer:

$atoms= 1.204x10^{24}atoms$

Explanation:

Hello!

In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:

$atoms=2.00mol*\frac{6.022x10^{23}atoms}{1mol} \\\\atoms= 1.204x10^{24}atoms$

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