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Alexxandr [17]
2 years ago
13

How many atoms of Kr (Krypton) are in a balloon that contains 2.00 mol of Kr? (4)

Chemistry
1 answer:
Svetllana [295]2 years ago
4 0

Answer:

atoms= 1.204x10^{24}atoms

Explanation:

Hello!

In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:

atoms=2.00mol*\frac{6.022x10^{23}atoms}{1mol} \\\\atoms= 1.204x10^{24}atoms

Best regards!

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