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Elanso [62]
3 years ago
15

I do not understand this question? Using partial quotients, which would be the best choice for the first number to subtract in t

he division problem 858 26? A.2,600 B.520 C.800 D.780
Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

B. 520

Step-by-step explanation:

Partial quotient is simply the method used to find the value of a quotient by dividing bits by bits until you get to the answer. For instance if you want to divide 124/4

Whatever closest multiple of 4 to 124 you remember, write it down. For instance I remember 80 first.

80 is the 20th multiple of 4 (80÷4 = 20).

Then subtract the number from the original number you want to divide

124 – 80 = 44

Again, write down the closest multiple of 44 you remember. To me is 40, and it is the 10th multiple.

Subtract 40 from 44 you have 4 left.

It's now easy to divide 4 by 4 which is 1.

To now get the quotient in total, you'll add up

20 + 10 + 1 = 31.

Therefore, to use partial quotient in this problem, the best choice to begin with will be 520 because it is the 20th multiple of 26. Although 780 is the 30th multiple of 26, 520 will be easier to remember. For this reason, it is the best choice.

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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
G(t) = 3t+ 4; Find g(−3)
lorasvet [3.4K]

Answer:

t=-5

Step-by-step explanation:

-3=3t+4

-1=t+4

-5=t

6 0
3 years ago
last night, julie's pet hamster zoe kept julie awake for at least an hour running on her exercise wheel and scratching at the co
borishaifa [10]

Answer: x+y\geq 1, x>\frac{1}{4} ,  x\geq 2y and y\geq 0

Step-by-step explanation:

Here,  x represents the number of hours Zoe spent running on her wheel and y represents the number of hours spent scratching her cage.

Julie was awoke for at least an hour running on her exercise wheel and scratching the of her cage.

⇒ x+y\geq 1

She ran on her wheel at least twice as long as she scratched at the corners of her cage.

⇒ x\geq 2y

Also, She spent more than 1/4 hour running on her wheel.

⇒ x>\frac{1}{4}

And, we know that number of hours can not be negative.

⇒  y\geq 0

Therefore, the complete system of inequality which shows the given situation is,

x+y\geq 1, x>\frac{1}{4} and x\geq 2y, y\geq 0

Note: the feasible region ( covered by the given system) is shown in the below graph.


6 0
3 years ago
What is the midpoint of (10,6) and (4,9)
Leona [35]

Answer:

The midpoint is (7,7.5)

4 0
3 years ago
2. Simplify the following expression 1 (16 (16-12)​
nikklg [1K]

Answer:

The answer is 64.

16-12=4.

4×16×1=64.

4 0
4 years ago
Read 2 more answers
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