<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. If the sum of the digits of the original number is 13, then find the number. </u>
<h3><u>Statement</u><u>:</u></h3>
<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. </u><u>T</u><u>he sum of the digits of the original number is 13</u><u>.</u>
<h3><u>Solution:</u></h3>
Let one of the digit of the original number be x.
So, the other digit = (13-x)
Therefore, the two digit number = 10(13-x) + x = 130-10x+x = 130-9x
The number obtained after interchanging the digits is 10x+(13-x) =9x+13
Therefore, by the problem
130-9x-(9x+13) = 45
or, 130-9x- 9x-13 = 45
or, -18x = 45-130+13
or, -18x= -72
or, x = 72/18 = 4
or, x = 4
So, the original number = 130-9x = 130 -9(4) = 130 - 36 = 94
<h3>Answer:</h3>
The number is 94.
I think the answer you have given isn't right. The answer should be 94.
The first digit after the decimal point is called the tenths place value. There are six tenths in the number O.6495. The second digit tells you how many hundredths there are in the number. The number O.6495 has four hundredths