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2 years ago

A lamp was on sale for 25% off its regular price of $80. Craig had a coupon that took an additional 25%

Mathematics

1 answer:

hram777 [196]2 years ago

6 0

Answer:

$45

Step-by-step explanation:

The sale price changed from $80 to 60, then with the coupon another 25% was taken off leading it to come to a price of $45

$80 x .75 = 60

$60 x .75 = 45

(.75 is for the price of the original value that he will be paying later)

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Match each pair of equivalent values.

vaieri [72.5K]

Answer:

1 - $1^{2}$

12 - ?

4 - square root of 16

64 - $8^{2}$

16 - $4^{2}$

2.828 - square root of 8

Step-by-step explanation:

I need more terms to match

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2 years ago

10. A soccer team is having a fundraiser by selling raffle tickets. Each ticket costs $2. For every 3 tickets

sergejj [24]

Answer:

Step-by-step explanation:

2 over 3 tickets subtract the 1 dollar discount

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3 years ago

Read 2 more answers

If the average (arithmetic mean) of 3a and 4b is less than 50, and a is twice b, what is the largest integer value of a?

sdas [7]

Answer: The largest value of 'a' is less than 20

Step-by-step explanation:

If arithmetic mean of 3a and 4b is less than 50 i.e 3a+4b/2 < 50

3a+4b < 100... (1)

If a is twice as b, a = 2b... (2)

Substituting equation 2 into 1 we have, 3(2b)+4b < 100

6b+4b < 100

10b < 100

b < 10

Since a = 2b, a = 2×10 = 20

Therefore the largest value of 'a' is less than 20 which can be 19.9

4 0

3 years ago

To save a woman from a burning building, the firemen placed a 10-meter ladder against the window. The foot of the ladder was 6 m

Dafna11 [192]

Answer:

The window is 8 meters high.

Step-by-step explanation:

8 0

2 years ago

The number of contaminating particles on a silicon wafer prior to a certain rinsing process was determined for each wafer in a s

Allushta [10]

Answer:

a) $P(X\geq 1) = 1-P(X$

b) $P(X\geq 5) = 1-P(X$

And replacing we got:

$P(X \geq 5) = 1-[0.01+0.02+0.03+0.12+0.11]=1-0.29=0.71$

Step-by-step explanation:

For this case we can solve this problem creating the following table

Number of particles Frequency Rel. Frequency

0 1 1/100 =0.01

1 2 2/100 =0.02

2 3 3/100=0.03

3 12 12/100=0.12

4 11 11/100=0.11

5 15 15/100=0.15

6 18 18/100=0.18

7 10 10/100=0.1

8 12 12/100=0.12

9 4 4/100=0.04

10 5 5/100=0.05

11 3 3/100=0.03

12 1 1/100=0.01

13 2 2/100=0.02

14 1 1/100=0.01

Total 100 1

We assume on this case the the relative frequency represent the probability.

Let X the number of contaminating particles on a silicon wafer

What proportion of the sampled wafers had at least one particle?

For this case we can use the complement rule like this:

$P(X\geq 1) = 1-P(X$

At least five particles?

Again for this case we can use the complement rule and we got:

$P(X\geq 5) = 1-P(X$

And replacing we got:

$P(X \geq 5) = 1-[0.01+0.02+0.03+0.12+0.11]=1-0.29=0.71$

5 0

3 years ago