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Romashka [77]
3 years ago
12

When table salt is placed in water and stirred it dissolves and a clear liquid is obtained. This process is a

Chemistry
1 answer:
Kobotan [32]3 years ago
3 0

I think the answer would be solution

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Convert the Following<br><br> 10 hm to cm
Alik [6]

Answer:

1x 10⁴ m or 1000 meters

Explanation:

1 hectometer = 100 meters

10 hectometers = 10 x 100 meters = 1000m

or in scientific form = 1 x 10⁴

4 0
3 years ago
Write a chemical equation for the dissolution of the AgCl precipitate upon the addition of NH,(aq).
Kobotan [32]

Explanation:

White precipitate of silver chloride get dissolves in excess ammonia to formation of complex between silver ions, chloride ions and ammonia molecules.

The chemical reaction is given as:

AgCl(s)+2NH_3(aq)\rightarrow Ag[(NH_3)_2]^+Cl^-(aq)

When 1 mole of silver chloride is added to 2 mole of an aqueous ammonia it form coordination complex of diaaminesilver(I) chloride.

7 0
3 years ago
What is the molecular geometry of a molecule made of two atoms that share one pair of electrons and have no lone electrons pairs
morpeh [17]

Answer:

linear

Explanation:

Actually I consulted various sources too and that was the most sought answer,I just decided to answer you before studying it too

5 0
3 years ago
How objects with different masses and volumes have the same density?​
AURORKA [14]

Answer:

mass and volume are independent. Two objects with the same volume can have different masses hence they can have different densities

Explanation:

The mass of atoms their size and how they are arranged determine the density

6 0
3 years ago
Consider the reaction. A(aq) = 2 B(aq) Kc = 6.90 x 10 6 at 500 K If a 3.00 M sample of A is heated to 500 K, what is the concent
kirza4 [7]

Answer:

0.004548 M is the concentration of B at equilibrium at 500 K.

Explanation:

                         A(aq) ⇆ 2 B(aq)

Initially               3.00 M

At equilibrium   3.00 -x    2x

Equilibrium constant of the reaction at 500 K =K_c=6.90\times 10^{-6}

Concentration of A at 500 K at equilibrium , [A] = (3.00 -x )M

Concentration of B at 500 K at equilibrium,[B]= 2x

An expression of equilibrium constant is given as:

K_c=\frac{[B]^2}{[A]}

6.90\times 10^{-6}=\frac{4x^2}{(3.00-x)}

On solving for x:

x = 0.002274 M

[B] = 2 x = 2 × 0.002274 M = 0.004548 M

[A] = (3-x) = 3 M - 0.002274 M =2.997726 M

0.004548 M is the concentration of B at equilibrium.

8 0
3 years ago
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