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Tpy6a [65]
2 years ago
13

A gas at 750 mmhg and with a volume of 2. 00 l is allowed to change its volume at constant temperature until the pressure is 600

mmhg. What is the new volume of the gas?
Chemistry
1 answer:
Gemiola [76]2 years ago
8 0

Answer:

The new volume of a gas at 750 mmhg and with a volume of 2. 00 l when allowed to change its volume at constant temperature until the pressure is 600 mmhg is 2.5 Liters.

Explanation:

Boyle's law states that the pressure of a given amount of gas is inversely proportional to it's volume at constant temperature. It is written as;

P ∝ V

P V = K

P1 V1 = P2 V2

Parameters :

P1 = Initial pressure of the gas = 750 mmHg

V1 = Initial pressure of the gas = 2. 00 Liters

P2 = Final pressure of the gas = 600 mmHg

V2 = Fimal volume of the gas = ? Liters

Calculations :

V2 = P1 V1 ÷ P2

V2= 750 × 2. 00 ÷ 600

V2 = 1500 ÷ 600

V2 = 2.5 Liters.

Therefore, the new volume of the gas is 2. 5 Liters.

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Identify two ways that temperature plays a role in chemical changes.
sergejj [24]

Answer:

Increasing the temperature will cause chemical changes to occur faster. Decreasing the temperature, causes the particles to lose energy which causes them to move around less and slower. The less they move, the less collisions occur, and the less reactions occur between the chemicals = slower reaction rate.

Explanation:

3 0
3 years ago
Plants undergo photosynthesis to produce glucose according to the reaction below. What mass of water is required to produce 5.0g
solniwko [45]

Answer:

option a) 3 g

Explanation:

mass of Glucose = 5 g

Mass of H₂O = ?

Reaction Given:

                   6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂

Solution:

First we have to find mass of glucose from balanced reaction.

So,

Look at the reaction

                        6CO₂ + 6H₂O -------> C₆H₁₂O₆ + 6O₂

                                     6 mol               1 mol

As 6 mole of water (H₂O) give 1 mole of Glucose (C₆H₁₂O₆ )

Convert moles to mass

molar mass of C₆H₁₂O₆  = 6(12) + 12(1) + 6(16)

molar mass of C₆H₁₂O₆  = 72 + 12 + 96

molar mass of C₆H₁₂O₆= 180 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now

             6CO₂      +  6H₂O          --------->     C₆H₁₂O₆   +    6O₂

                              6 mol (18 g/mol)           1 mol (180 g/mol)

                                  108 g                            180 g

108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆)

So

if 108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆) so how many grams of water (H₂O) will be required to produce 5 g of glucose (C₆H₁₂O₆).

Apply Unity Formula

               108 g of water (H₂O) ≅ 180 g of glucose (C₆H₁₂O₆)

                X g of water (H₂O) ≅ 5 g of glucose (C₆H₁₂O₆)

Do cross multiply

                     mass of water (H₂O) = 108 g x 5 g / 180 g

                     mass of water (H₂O) = 3 g

So 3 g of water is required to produce 5 g of glucose.  

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Answer:

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actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2

Because the actual mole ratio of NO:O2 is larger than the balanced equation mole

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Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO

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Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2

Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N

Explanation:

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