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steposvetlana [31]
2 years ago
7

a bag contains 1 red beads 2 yellow beads 2 green beads and 1 blue bead a bean is choose and at random what is the probability t

hat is green​
Mathematics
1 answer:
Kisachek [45]2 years ago
4 0

Answer:

Step-by-step explanation:

Add all the beads together to get your total amount of beads (This will be your denominator)

1+2+2+1=6 beads in total

You only want to focus on the amount of green beads. (Which is 2 and that will be you numerator)

\frac{Numerator}{Demonator}=\frac{green beads}{Total amount of beads}

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The table shows the number of each type of toy in the store. the toys will be placed on shelves so that each shelf has the same
skelet666 [1.2K]
First, we compute the highest common factor between the numbers of toys. The highest common factor for 45, 105 and 75 is 15. Therefore, we will need 15 shelves. On each shelf, there will be 45/15 = 3 dolls, 105/15 = 7 footballs and 75/15 = 5 small cars
3 0
3 years ago
Consider the following system of equations:
Kobotan [32]

Answer:

x=-15, y=25. (-15, 25).

Step-by-step explanation:

2x+3y=45

x+y=10

--------------

x=10-y

2(10-y)+3y=45

20-2y+3y=45

20+y=45

y=45-20

y=25

x+25=10

x=10-25

x=-15

5 0
3 years ago
Read 2 more answers
10p-2(3p-6)=4(3p-6)-8p
lisabon 2012 [21]

Answer:

undefined / no solution

Step-by-step explanation:

10p - 2(3p-6) = 4(3p-6) - 8p

10p - 6p - 12 = 12p - 24 - 8p

4p - 12 = 4p - 24

0 = -12

0 cannot equal -12

4 0
2 years ago
Matt buys 14 jars of paint. Each jar contains 300 milliliters of paint. How many liters of paint in all is there in the jars?
SpyIntel [72]

Answer:

4200 milliliters

hope this helped! <3

-bubb0

3 0
3 years ago
Read 2 more answers
3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall
Katen [24]

Answer:

The volume of the toy is V=5.23\ ft^3

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

V=\frac{2}{3}\pi r^{3}

In this problem, the wide of the toy is equal to the diameter of the hemisphere

so

D=2\ ft

r=2/2=1\ ft ----> the radius is half the diameter

substitute

V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3

step 2

Find the volume of the cone

The volume of the cone is given by

V=\frac{1}{3}\pi r^{2}h

we know that

The radius of the cone is the same that the radius of the hemisphere

so

r=1\ ft

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

h=4-1=3\ ft

substitute the given values

V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

so

V=(\frac{2}{3} \pi+\pi)\ ft^3

V=(\frac{5}{3}\pi)\ ft^3

assume

\pi=3.14

V=\frac{5}{3}(3.14)=5.23\ ft^3

5 0
3 years ago
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