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miss Akunina [59]
2 years ago
15

Suppose you needed to push a 1,500-N sofa up a frictionless ramp with a 30° angle. How much force would you have to apply to the

sofa?Show your work below.
Physics
1 answer:
Ksivusya [100]2 years ago
4 0

Answer:

1299N

Explanation:

GIven data

Weight W= 1500N

Angle Ф= 30°

The applied force up the frictionless ramp is gotten by applying the formula below

F= WcosФ

substitute

F=1500 cos 30

F = 1500*0.8660

F= 1299N

Hence the applied force is 1299N

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The graph below shows the speed of a car as it drives along a racetrack.
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Surprise surprise ! The area under a speed/time graph is the distance covered during that time !

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3 years ago
A satellite that goes around the earth once every 24 hours (86,400 s) is called a geosynchronous satellite. If a geosynchronous
Olegator [25]

Answer:

42244138.951 m

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G = Gravitational constant = 6.667 × 10⁻¹¹ m³/kgs²

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v=\frac{2\pi \times r}{24\times 3600}

The Centripetal force of the satellite is balanced by the universal gravitational force

m\frac{v^2}{r}=\frac{GMm}{r^2}\\\Rightarrow \frac{\left(\frac{2\pi \times r}{24\times 3600}\right)^2}{r}=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{r^2}\\\Rightarrow \left(\frac{2\pi \times r}{24\times 3600}\right)^2=6.667\times 10^{-11}\times 5.98\times 10^{24}\\\Rightarrow r^3=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\\\Rightarrow r=\left(\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\right)^{\frac{1}{3}}\\\Rightarrow r=42244138.951\ m

The radius as measured from the center of the Earth) of the orbit of a geosynchronous satellite that circles the earth is 42244138.951 m

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