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Rainbow [258]
2 years ago
11

Zeb was lifting a box onto a moving truck. He lifted with a net force of 2000N and the box had a mass of 100 kg. What was the re

sulting acceleration?
Physics
1 answer:
Aleksandr [31]2 years ago
8 0

Answer:

<h2>20 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{2000}{100}  = 20 \\

We have the final answer as

<h3>20 m/s²</h3>

Hope this helps you

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Korolek [52]

Have an amazing day you are an amazing person:)

5 0
2 years ago
Which pair shows the law of reflection?<br> O A and B<br> O A and C<br> O A and D<br> O A and E
Elanso [62]
A and C

Imagine u are shooting a laser pointer at a mirror this is pretty much what it is
5 0
2 years ago
How mmany bonds should be drawn in the lewis- dot structure for methan, CH4
Yakvenalex [24]
Since carbon has 4 valence electrons, a total of 4 bonds will be drawn withing methane, one between each H and the center C

Hope this helps
6 0
3 years ago
The mechanical energy of a bicycle at the top of a hill is 6,000 J. The bicycle stops at the bottom of the hill by applying the
Semmy [17]

Answer:

Thermal energy produce =4,000 J.

Explanation:

Given that

Mechanical  energy at the top of hill = 6,000 J

Mechanical  energy at the bottom of hill = 2,000 J

We know that energy is conserve

Energy at top of hill = energy at bottom of hill + Thermal energy produce

So now by putting the values

Energy at top of hill = energy at bottom of hill + Thermal energy produce

6,000 = 2,000+ Thermal energy produce

Thermal energy produce =6,000-2,000 J

Thermal energy produce =4,000 J.

As we know that thermal energy produce due to friction when one mechanical component slides on the other mechanical component then always heat is generated and this heat is known as thermal energy.

7 0
3 years ago
Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.
8_murik_8 [283]

The electric potential is a scalar unit, so we don't have to struggle with the vectors. The formula that gives electric potential is

V = \frac{1}{4\pi\epsilon_0}\frac{q}{r}

1) At point a, the electric potential is the sum of the potentials due to q1 and q2. So,

V_a = \frac{1}{4\pi\epsilon_0}\frac{q_1}{r_1} + \frac{1}{4\pi\epsilon_0}\frac{q_2}{r_2}

The distance from the center of the square to one of the corners is \sqrt2 L/2 = 0.035m

V_a = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.035} + \frac{1}{4\pi\epsilon_0}\frac{-2\times10^{-6}}{0.035} = 0

The answer is zero, because the point charges are at equal distances and their magnitudes are also equal but their directions are opposite.

2) V_b = \frac{1}{4\pi\epsilon_0}\frac{q_1}{r_1} + \frac{1}{4\pi\epsilon_0}\frac{q_2}{r_2}

r_1 = 0.05\sqrt2m\\r_2 = 0.05m

V_b = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.05\sqrt2} + \frac{1}{4\pi\epsilon_0}\frac{-2\times10^{-6}}{0.05}\\V_b = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.05} (\frac{1}{\sqrt2}-1)\\V_b = \frac{1}{4\pi\epsilon_0} (4\times 10^{-5})(-0.29)\\V_b = (-\frac{2.9\times10^{-6}}{\pi\epsilon_0})[tex]3) The work done on q3 by q1 and q2 is equal to the difference between  energies. This is the work-energy theorem. So,[tex]W = U_b - U_a

U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_3}{r} = Vq_3

W = q_3(V_b - V_a) = q_3(V_b - 0)\\W = (-2\times10^{-6})(-\frac{2.9\times10^{-6}}{\pi\epsilon_0})\\W = \frac{5.8\times10^{-12}}{\pi\epsilon_0}

4 0
2 years ago
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