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vagabundo [1.1K]
2 years ago
6

Why do waves with frequencies higher than visible light hurt while those with lower frequencies do not affect us?

Physics
2 answers:
STALIN [3.7K]2 years ago
7 0
Lower frequency waves have less strength to penetrate. How bad a wave is all depends on how well it penetrates our bodies. Visible light doesn't penetrate ur skin, but UV rays (higher than visible) can go through our skin, making it <span>bad" for us. High frequency waves have more energy and move faster</span>
AnnZ [28]2 years ago
4 0

Answer:

Explanation:

Waves with higher frequency have high penetration power. Energy of a wave id directly proportional to the frequency of the wave so penetration power is high. Visible rays suits to the human body and do not harm. Humans can see visible light and can easily work in visible range. But in the higher frequency such as UV waves and radio waves penetrate human body and affect it in negative way.

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A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from zero to 5.27 m
jeyben [28]

Answer:

See explanation

Explanation:

From Newton's law; the rate of change of momentum is proportional to the impressed force. Hence;

F.t = mv- mu

F= force

t= time

m= mass

V= final velocity

u = initial velocity

since u = 0, mv= 0

F= MV/t

F= 69.8 × 5.27/0.833

F= 442 N

Impulse = Ft= 442 × 0.833= 368 Ns

5 0
2 years ago
An arrow of mass 415 g is shot at a target with a speed of 68.5m/s. The target, which has a mass of 3.3 kg, is moving toward the
Murrr4er [49]

The velocity of the target and arrow after collision is 6.67m/s

<u>Explanation:</u>

Given:

Mass of arrow, mₐ = 415g

Speed of arrow, vₐ = 68.5m/s

Mass of the target, mₓ = 3.3kg = 3300g

speed of the target, vₓ = -1.1m/s (Because the target moves in opposite direction

Velocity of the target and arrow after collision, vₙ = ?

Applying the conservation of momentum,

mₐvₐ + mₓvₓ = (mₐ+mₓ) vₙ

415 X 68.5 + 3300 X -1.1 = (415+3300) X vₙ

28427.5 - 3630 = 3715 X vₙ

24797.5 = 3715 X vₙ

vₙ = 6.67m/s

Therefore, the velocity of the target and arrow after collision is 6.67m/s

4 0
3 years ago
When throwing a ball upwards, the velocity is positive, and the acceleration is negative. True of False?
Setler79 [48]

Answer:

The velocity & acceleration will be taken as negative when a ball is thrown upward because work is done against the gravity.

Explanation:

3 0
2 years ago
How long does it take for a truck accelerating at 1.5 m/s^2 to got from rest to 75 km/hr
Free_Kalibri [48]

Answer:

t = 13.9s

Explanation:

u = 0 m/s

v = 75 km/h

= 20.83 m/s

a = 1.5 m/s²

Using

v = u + at

20.83 = 0 + 1.5t

t = 13.9s

6 0
3 years ago
You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up. The ruler
scZoUnD [109]

Answer:

q=1.4*10^{-9}C

Explanation:

Given data:

charge on ruler = -14μC

Mass of tissue is 5 g

To Know the minimum charge,  equate electrostatic force to weight  

we have F = W

so\frac{KQq}{r^2} =mg

putting all value in equation,

=\frac{9*10^9*(14*10^{-6})*q}{0.06^2} = 5* 10^{-3}*9.8

solving for q

q =\frac{5* 10^{-3}*9.8 *0.06^2}{9*10^9*(14*10^{-6})}

or q=1.4*10^{-9}C

5 0
3 years ago
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