We calculate current from the formula:

, where q is a electric charge transferred over time t
Time should be converted to seconds:
1h 15 min= 75min= 4500s
I=

Result is in unit-Ampere
Answer:
d₁ = 0.29 in
d₂ = 0.505 in
Explanation:
Given:
T = 1500 lbf in
L = 10 in
x = 0.5 L = 5 in

First case: T = T₁ + T₂
T₂ = T - T₁ = 1500 - 750 = 750 lbf in
If the shafts are in series:
θ = θ₁ + θ₂
θ = ((T₁ * L₁)/GJ) + ((T₂ * L₂)/GJ)
Second case: If d₁ ≠ d₂
θ = ((T₁ * L₁)/GJ₁) + ((T₂ * L₂)/GJ₂) = 0 (eq. 1)
t₁ = t₂
(eq. 2)
T₁ + T₂ = 1500 (eq. 3)
θ₁ first case = θ₁ second case
Replacing:

The same way to θ₂:

From equation 2, we have:
d₁ = 0.587 * d₂
From equation 3, we have:
d₂ = 0.505 in
d₁ = 0.29 in
Can you give me the choices.<span />
Acceleration = (change in speed) / (time for the change)
Change in speed = (ending speed) - (starting speed)
Change in speed = (60 km/hr) - (50 km/hr) = 10 km/hr
Time for the change = 12 sec
Acceleration = (10 km/hr) / (12 sec)
Acceleration = 0.8333 km/hr-sec
Convert to a unit that we can understand:
Acceleration = (0.8333 km/hr-sec)x(1000 m/km)x(hr/3600sec)
Acceleration = (833.3 / 3600) (m-hr / hr-sec²)
Acceleration = (833.3 / 3600) (m/s²)
<em>Acceleration = 0.231 m/s² </em> or 0.833 km/hr-sec²