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2 years ago

What are the slope and y-intercept for the graph of y – 3x = -1?

Mathematics

1 answer:

Liula [17]2 years ago

5 0

Answer:

Slope (m) = 3, y-intercept (b) = -1

Step-by-step explanation:

First, we need to write the equation in y = mx + b.

To do this, add 3x to both sides.

y = 3x - 1 is your result.

Now, we have everything we need to do determine our slope and y-intercept in just this equation alone.

Remember, m = slope and b = y-intercept.

In this equation:

m = 3

b = -1

So your slope is 3, and your y-intercept is -1

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If g(x ) = 3x - 5, then g -1(x )=

NemiM [27]

G(x) = 3x - 5

let g(x) = y

y = 3x - 5

y + 5 = 3x

3x = y + 5

x = (y + 5)/3

From y = g(x), x = g⁻¹(y)

x = (y + 5)/3

g⁻¹(y) = (y + 5)/3

g⁻¹(x) = (x + 5)/3

6 0

2 years ago

-x + 2y = 3 2x – 3y = -6

s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

Given equations :- 

-x + 2y = 3 ....... ( i )

2x - 3y = -6 ....... ( ii )

From ( i ) 

-x + 2y = 3

-x = 3 - 2y

x = 2y - 3 ........ ( iii )

From ( ii ) 

2x - 3y = -6

2x = -6 + 3y

$x = \frac{ - 6 + 3y}{2}$

........ ( iv )

Equating ( iii ) and ( iv )

x = x

$2y - 3 = \frac{ - 6 + 3y}{2}$

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

4 0

2 years ago

find the area of a parallelogram if a base and corresponding altitude have the indicated lengths base 1 1/2 feet , altitude 6 in

Ostrovityanka [42]

The area of parallelogram is 108 square inches

Solution:

The formula for area of parallelogram is:

$Area = base \times height$

From given,

$Base = 1\frac{1}{2}\ feet = \frac{2 \times 1 + 1}{2} = \frac{3}{2}\ feet$

$Height = 6\ inches$

Convert feet to inches

1 feet = 12 inches

$\frac{3}{2}\ feet = \frac{3}{2} \times 12\ inches = 18\ inches$

Therefore, area of parallelogram is:

$Area = 18 \times 6\\\\Area = 108$

Thus area of parallelogram is 108 square inches

4 0

2 years ago

The lock is numbered from 0 to 49. Each combination uses three numbers in a right, left, right pattern. Find the total number of

sineoko [7]

Answer:

147

Step-by-step explanation:

8 0

2 years ago

Round up to the nearest hundredth

Shalnov [3]

$x^2+3x-5=0\\\\a=1;\ b=3;\ c=-5\\\\b^2-4ac=3^2-4\cdot1\cdot(-5)=9+20=29\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-3-\sqrt{29}}{2\cdot1}=\dfrac{-3-\sqrt{29}}{2}\approx-4.19\\\\x_2=\dfrac{-3+\sqrt{29}}{2\cdot1}=\dfrac{-3+\sqrt{29}}{2}\approx1.19$

5 0

3 years ago