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3 years ago

11

there are 120 children standing in a line,every third gets a rubber, every fourth child gets ruler and every fifth gets a book.

in what position is the first child that gets all 3 items?

2 answers:

Kaylis [27]3 years ago

8 0

Answer:

60th position is the first child that gets all 3 items

Step-by-step explanation:

Find the LCM of 3 , 5 and 4.

Least common multiple of 3 , 4 and 5 = 3 * 4 * 5 = 60

Goshia [24]3 years ago

7 0

Answer:

3,6,9,12,

4,8,12,16,

5,10,15,

in 60th position

60is the first number that can be divided by 60/3=20 60/4=15 60/5=12

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PLZ CHECK MY ANSWERS AND TELL ME THE RIGHT ANSWERS IF I GET THEM WORNG

Natalija [7]

Answer:

Step-by-step explanation: I Can Tell You The First One Is Correct And I Believe The Second Was Is Too.

7 0

3 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago

(1) The point R is halfway between the -6 and -5 on the number line below and represents the number ____. (Use the hyphen for ne

avanturin [10]

-5.5 is halfway between -6 and -5

7 0

3 years ago

Read 2 more answers

Use Midpoint and Slope Formulas to complete the tables below.1. Find the midpoint of RP, given the coordinates R (5, 8) and P (3

poizon [28]

The midpoint formula for a segment is:

$x_m,y_{_m}=\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2}$

apply to points R and P

$\begin{gathered} x_m,y_m=\frac{(5+3)}{2},\frac{(8+6)}{2} \\ x_m,y_m=\frac{8}{2},\frac{14}{2} \\ x_m,y_m=(4,7) \end{gathered}$

using the definition of slope find the slope of the segment

$m=\frac{y_2-y_1}{x_2-x_1}$

apply to points R and P

$\begin{gathered} m=\frac{8-6}{5-3} \\ m=\frac{2}{2} \\ m=1 \end{gathered}$

to lines are parallel when the slopes are the same

$\mleft\Vert m=1\mright?$

two lines are perpendicular when the product of the slopes is equal to -1

$\begin{gathered} m\cdot\perp m=-1 \\ 1\cdot\perp m=-1 \\ \perp m=-\frac{1}{1} \\ \perp m=-1 \end{gathered}$

7 0

1 year ago

117.369 is 24 3/10% of what number?

Tanya [424]

Let's look at the equation:
0.243x=117.369
Divide each side by 0.243.
X=483
So, the number is 483.

4 0

3 years ago