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gogolik [260]
3 years ago
14

Can someone cashapp me 12 dollars and I pay them back? It’s an emergency

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

Wait why

Step-by-step explanation:

I don't understand can you ask your parents or friends. I don't give strangers money.

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PLZZZZ HELPPPPPPPPP!!!! a survey asks teachers and students whether they would like the new school mascot to be a Viking or a Pa
VARVARA [1.3K]

Answer:

B

Step-by-step explanation:

Two events A and B are called independent, when

P(B|A)=P(B),

where P(B|A) is the probability that B occurs given that A has already occurred.

A = randomly selected person is a student

B = randomly selected person prefer "Vikings"

B|A = randomly selected student prefer "Vikings"

Probabilities:

P(A)=\dfrac{100}{125}=\dfrac{4}{5}=0.8\\ \\P(B|A)=\dfrac{80}{85}=\dfrac{16}{17}\approx 0.94

Since

0.80\neq 0.94

we can state that events are not independent.

8 0
3 years ago
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Which TWO numbers round to 3 as the nearest whole number?
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B and F , wish you the best enjoy!
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Write the expression as a product:<br><br> (x+3)2–1
daser333 [38]

this is it..............

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3 years ago
Who can answer the 3x+2y=-6 for the intercepts and to graph it ?? I'm so lost
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x-intercept: 2

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3 years ago
Please help
Alekssandra [29.7K]

Answer:

25 in x 15 in

Step-by-step explanation:

Given:

  • Length = 3/5 the width
  • Area = 375 in²

Let width = x

Therefore, length = 3/5 x

First create an equation for the area of the picture based on the given information for its width and length:

\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}

We are told the area of the enlarged picture is 375 in².  Therefore, substitute this into the equation and solve for x to find the width of the enlarged picture:

\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}

Therefore, the width of the enlarged picture is 25 in.

Substitute the found value of x into the expression for length to find the length of the enlarged picture:

\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>.  The width is 25 in and the length is 15 in, as the length is 3/5 of the width.

5 0
2 years ago
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