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egoroff_w [7]
3 years ago
15

How can you use a screen to determine whether an image is real or virtual?

Physics
1 answer:
pychu [463]3 years ago
6 0
Real images are those where light actually converges, whereas virtual images are locations from where light appears to have converged
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An object goes from a speed of 9m/s to a total stop in 3 s. what is the object's acceleration
timama [110]
A = dv/dt = ak
ak = ( 0.0 m/s - 9.0 m/s ) / ( 3 s )

3m/s^2
3 0
4 years ago
an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the
Gnom [1K]

The current drawn by the electric frying pan is <u>27.295 A.</u>

<u />

Power of toaster, P1 = 1800 W

Power of electric frying pan, P2 = 1400 W

Power of lamp, P3 = 75 W

Three devices are in parallel combination. So their Voltage difference is the same.

∆V = 120 Volt

Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A

Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A

Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A

Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A

Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.

The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.

Learn more about current here:-brainly.com/question/24858512

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8 0
2 years ago
In a ruby laser, an electron jumps from a higher energy level to a lower one. if the energy difference between the two levels is
Vaselesa [24]

The wavelength of the emitted photon is(\lambda)= 690nm

<h3>How can we calculate the wavelength of the emitted photon?</h3>

To calculate the wavelength of the photon we are using the formula,

\triangle E= \frac{h\times c}{\lambda}

Or,\lambda= \frac{h\times c}{\triangle E}

We are given here,

\triangle E= The energy difference between the two levels = 1. 8 ev= 1.8\times 1.6 \times 10^{-19} C.

h= Planck constant = 6.626\times 10^{-34} Js.

c= speed of light = 3\times10^8 m/s.

We have to find the wavelength of the emitted photon =\lambda m.

Therefore, we substitute the known parameters in the above equation, we can find that,

\lambda= \frac{h\times c}{\triangle E}

Or,\lambda= \frac{6.626\times 10^{-34}\times 3\times 10^8}{1.8\times 1.6 \times 10^{-19}}

Or,\lambda= 690\times 10^{-9} m

Or,\lambda=690 nm.

From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.

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brainly.com/question/17245697

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8 0
2 years ago
What is the net force on the box?
omeli [17]

Answer:

The magnitude of the force net is an acting object multiplied by acceleration of the object

5 0
3 years ago
A U-tube is open to the atmosphere at both ends. Water is poured into the tube until the water column on the vertical sides of t
zmey [24]

Answer:

The value is  \Delta h  =  0.003 \  m

Explanation:

From the question we are told that

   The  height of the water is  h_1  =  10 \ cm  =  0.10 \  m

    The  density of  oil is \rho_o  =  950 \  kg/m^3

  The  height of  oil  is  h_2  =  6 \ cm  =  0.06 \  m

Given that both arms of the tube are open then the pressure on both side is the same

So  

      P_a =  P_b

=>   Here  

             P_a  =  P_z + \rho_w  *  g *  h

where  \rho_w is the density of water with value  \rho_w =  1000 \ kg/m^3

and  P_z is the atmospheric pressure

and  

        P_b  =  P_z + \rho_o  *  g *  h_2

=>   P_z + \rho_w  *  g * h =    P_z + \rho_o  *  g *  h_2

=>    \rho_w   * h  =    \rho_o  *  h_2

=>      h  =  \frac{950 * 0.06 }{1000}

=>      h  = 0.057 \ m

The  difference in height is evaluated as    

           \Delta h  =  0.06 - 0.057

          \Delta h  =  0.003 \  m

     

6 0
4 years ago
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