Answer:
B) R1 = 6 V and R2 = 6V
Explanation:
In series, both resistors will carry the same current.
that current will be I = V/R = 12 / (10 + 10) = 0.6 A
The voltage drop across each resistor is V = IR = 0.6(10) = 6 V
Answer:
very small solid particles called interstellar dust.
Explanation:
In the space between the stars there is gas and dust, which represent at least 20% of the mass of our galaxy. In the Milky Way it is considered that there is a gas density of approximately 0.2 to 0.5 atoms / cm3 in the surroundings of the Sun; with respect to the dust an average of 1 g / cm3 is estimated.
Gas is about atoms and molecules, mainly hydrogen; In order of abundance, helium, carbon, oxygen, nitrogen and iron follow. On the other hand, the dust is tiny particles, generally smaller than 10 microns; the dust does not shine and therefore it is only distinguished when it is projected on bright regions (nebulae or clusters).
Interstellar matter is mainly concentrated towards the plane of the galaxy, in the strip corresponding to the Milky Way; there you can see bright nebulas of diffuse character called nebulas. These nebulae are classified according to three types: (a) bright or emission nebulae, (b) reflection nebulae and (c) planetary nebulae.
Hydrogen appears both ionized and neutral; The bright nebulae are composed of ionized hydrogen and other ionized elements. Non-ionized (neutral) hydrogen is found in the spiral arms of the Milky Way and can be detected through radio waves.
Answer:
90 meters
Explanation:
Given:
x₀ = 0 m
v₀ = 0 m/s
v = 30 m/s
t = 6 s
Find:
x
x = x₀ + ½ (v + v₀)t
x = 0 + ½ (30 + 0)(6)
x = 90
The car travels 90 meters.
Given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.
<h3>What is Current?</h3>
Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.
If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;
I = Q/t
Where Q is the charge and t is time elapsed.
Given the data in the question;
- Time elapsed t = 1hr = 3600s
- Current I = 350mA = 0.35A
We substitute our given values into the expression above to determine the charge.
I = Q/t
Q = I × t
Q = 0.35A × 3600s
Q = 1260C
Therefore, given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.
Learn more about current here: brainly.com/question/3192435
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