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ryzh [129]
3 years ago
6

Single Factor ANOVA is a method we use when we want to compare a quantitative variable among more than two categories.

Mathematics
1 answer:
Goryan [66]3 years ago
3 0

Answer:

The given statement is "True".

Step-by-step explanation:

A statistical analytical technique that divides the perceived aggregate unpredictability present throughout an information source even further into 2 components.

  • Systemic components
  • Random components

If relevant information yet another category independent variable, as well as another quantifiable variable of interest, has been obtained, are using a single-way ANOVA.

Thus the above is the true answer.

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Find the measure of the angle indicated
Grace [21]

Answer:

86

Step-by-step explanation:

y + 28 + 58 = 180

y + 86 = 180

y = 180 - 86

y = 94

x + y = 180

x + 94 = 180

x = 180 - 94

x = 86

6 0
3 years ago
What is 10^-3x*10^x= 1/10
densk [106]
Since 1/10=10^-1, and multiplying exponents with the same base just adds the actual exponents at the top, x=2
3 0
3 years ago
Add the two expressions.<br> 32 – 4 and 2z + 5<br><br><br> Pls help quick!
alexgriva [62]

Answer:

2z + 33

Step-by-step explanation:

Add like terms like below:

(32 - 4) + (2z + 5) = 28 + 2z + 5

Combine like terms again:

(28 + 5) + 2z = 33 + 2z or 2z + 33

7 0
3 years ago
Where is the function f(x)=3x^2-6x-45/x^2-5x discontinuous, and what types of discontinuities does it have?
Vedmedyk [2.9K]

Answer:

Below.

Step-by-step explanation:

f(x)=3x^2-6x-45/x^2-5x

= 3x^2-6x-45 / (x(x - 5))

The denominator is zero when x - 0 and x = 5.

So there will be a vertical asymptote  at x = 0 and a hole at x = 5.

If we do the division  we get f(x)  = 3  remainder 9x - 45

so there will also be a horizontal asymptote where x = 3.

5 0
2 years ago
Read 2 more answers
Joel can drive his car 450 miles at a steady speed using 15 gallons of gasoline. Making rate table showing the number of miles y
harkovskaia [24]
I hope this helps!! Don’t mind the 20 mph at the top. That was from another problem I was helping someone else on.

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