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Alchen [17]
3 years ago
11

Can someone help me with the question in the image please i will mark as brainlyest if correct

Mathematics
1 answer:
nadya68 [22]3 years ago
3 0

Answer:

a

Step-by-step explanation:

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How do solve this problem 2/3 (2/8 + 4/8) =
scoundrel [369]

Answer:

1/2

Step-by-step explanation:

2/3 (2/8 + 4/8) =

First simplify what is inside the parentheses

2/8+4/8 = 6/8

Replace with 6/8

2/3 (6/8) =

Then multiply

2*6 =12

3*8 = 24

12/24

Divide top and bottom by 12

1/2

6 0
4 years ago
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What is the answer for this 3x+4x+5x+...+43x
sweet-ann [11.9K]

Answer:

1032x

Step-by-step explanation:

3x+4x+\cdots+43x=x(3+4+\cdots+45) \\ \\ =43x\left(\frac{45+3}{2} \right) \\ \\ =43(24x) \\ \\ =1032x

7 0
2 years ago
Can someone please help me??????
Ann [662]
All sides of a triangle must add up to 180.  89 + 59 = 148.  180 - 148 = 32.
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4 years ago
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The perimeter of a rectangle is 256 units. The longer sides are each 12 units more than the shorter sides. What is the length of
antoniya [11.8K]

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58 58 60 60 are the lengths of the sides

Step-by-step explanation:

7 0
3 years ago
Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure
Umnica [9.8K]

Answer:

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equations are  x₁+4 x₂ = 11 ...(i)

                                 2 x₁ + 7 x₂= 18 ...(ii)

The matrix form

                                A X = B

            \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

<u>Step(ii):-</u>

      \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

The Augmented Matrix form is

[AB] = \left[\begin{array}{ccc}1&4&11\\2&7&18\\\end{array}\right]

Apply Row operations,  R₂ → R₂-2 R₁

[AB] = \left[\begin{array}{ccc}1&4&11\\0&-1&-4\\\end{array}\right]  

The matrix form

                   \left[\begin{array}{ccc}1&4\\0&-1\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\-4\\\end{array}\right]

The equations are

                     x₁ + 4 x₂ = 11 ...(a)

                         - x ₂ = - 4

                            x ₂ = 4

Substitute   x ₂ = 4 in equation (a)

                      x₁ + 4 x₂ = 11

                      x₁ = 11 - 16

                        x₁ = -5

<u>Final answer</u>:-

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

7 0
3 years ago
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