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lesya [120]
3 years ago
6

Use the Distributive Property to REWRITE 6x(2y - 4x + 1)

Mathematics
1 answer:
BartSMP [9]3 years ago
5 0

Answer:

−24x2+12xy+6x

Step-by-step explanation:

6x(2y−4x+1)

=(6x)(2y+−4x+1)

=(6x)(2y)+(6x)(−4x)+(6x)(1)

=12xy−24x2+6x

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Step-by-step explanation: :)

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I don't know how to do things like this :(​
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Answer:

Step-by-step explanation:

i think its a

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Do y'all understand this question if so plz help ASAP....
Afina-wow [57]

Answer:

6394

Step-by-step explanation:

WXYZ

X < Z

Z = ⅔W

W = ⅔Y

Y = 3X

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Z = ⅔(2X) = (4/3)X

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7 0
3 years ago
A student solves the following equation and
Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}

\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)

\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)

\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)

as

  • \frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)
  • -\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a
  • \frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2

so equation becomes

3\left(a-2\right)-6a=a+2  

-3a-6=a+2

-3a-6+6=a+2+6

-4a=8

\mathrm{Divide\:both\:sides\:by\:}-4

\frac{-4a}{-4}=\frac{8}{-4}

a=-2

\mathrm{Verify\:Solutions}

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}

\mathrm{Solve\:}\:a+2=0:\quad a=-2

\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2

\mathrm{Solve\:}\:a-2=0:\quad a=2

So the following points are undefined

a=-2,\:a=2

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0
3 years ago
What is the elimination to this solution i think its b
Blababa [14]

EXPLANATION:

To get the solution of the simultaneous equation, using the elimination method:

We will have the following steps:

Step 1:

Write the two equations:

\begin{gathered} y=-\frac{1}{2}x+3 \\ y=-\frac{7}{2}x-3 \end{gathered}

Step2: Subtract the two equations:

\begin{gathered} y-y=-\frac{1}{2}x-(-\frac{7}{2}x)+3-(-3) \\ 0=-\frac{1}{2}x+\frac{7}{2}x+6 \\  \end{gathered}

Step 3: Simplify the expression

\begin{gathered} 0=3x+6 \\ 3x=-6 \\ x=-\frac{6}{3} \\ x=-2 \end{gathered}

Step 4: Substitute x=-2 into the formula:

\begin{gathered} y=-\frac{1}{2}x+3 \\ y=-\frac{1}{2}\times-2+3 \\ y=1+3 \\ y=4 \end{gathered}

Therefore, the answer is

(-2,4)

Thus,

Option B is correct

5 0
1 year ago
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