Answer:
Explanation:
velocity of ship with respect to water = 6.5 m/s due north
velocity of water with respect to earth = 1.5 m/s at 40° north of east
velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth
The magnitude of the velocity of ship relative to earth is 
= 5.66 m/s
We use the formula V=IR where I is current, v is voltage, and R is resistance. This is V=(3)(10) which is 30 Volts, answer choice (c)
Answer:
Explanation:
When we are driving we need a lot of attention and concentration. Also one involved in driving should be consious and courteous
Thus, whenever a person is drives, and when he is disactracted by Mobile phones it will destroy his presence of mind.
It will good if use mobile after stopping the vehicle
Thanks
Answer:
2.69 m/s
Explanation:
Hi!
First lets find the position of the train as a function of time as seen by the passenger when he arrives to the train station. For this state, the train is at a position x0 given by:
x0 = (1/2)(0.42m/s^2)*(6.4s)^2 = 8.6016 m
So, the position as a function of time is:
xT(t)=(1/2)(0.42m/s^2)t^2 + x0 = (1/2)(0.42m/s^2)t^2 + 8.6016 m
Now, if the passanger is moving at a constant velocity of V, his position as a fucntion of time is given by:
xP(t)=V*t
In order for the passenger to catch the train
xP(t)=xT(t)
(1/2)(0.42m/s^2)t^2 + 8.6016 m = V*t
To solve this equation for t we make use of the quadratic formula, which has real solutions whenever its determinat is grater than zero:
0≤ b^2-4*a*c = V^2 - 4 * ((1/2)(0.42m/s^2)) * 8.6016 m =V^2 - 7.22534(m/s)^2
This equation give us the minimum velocity the passenger must have in order to catch the train:
V^2 - 7.22534(m/s)^2 = 0
V^2 = 7.22534(m/s)^2
V = 2.6879 m/s
The answer is A. locations by the ocean typically do not get as cold in the winter or as hot in the summer as locations that are located inland.
