The intensity on a screen 20 ft from the light will be 0.125-foot candles.
<h3>What is the distance?</h3>
Distance is a numerical representation of the length between two objects or locations.
The intensity I of light varies inversely as the square of the distance D from the source;
I∝(1/D²)
The ratio of the intensity of the two cases;
![\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\ I_2= 0.125 \ foot-candles](https://tex.z-dn.net/?f=%5Crm%20%5Cfrac%7BI_1%7D%7BI_2%7D%20%3D%28%5Cfrac%7BD_2%7D%7BD_1%7D%20%29%5E2%5C%5C%5C%5C%20%5Crm%20%5Cfrac%7B2%7D%7BI_2%7D%20%3D%28%5Cfrac%7B20%7D%7B5%7D%20%29%5E2%5C%5C%5C%5C%20%5Cfrac%7B2%7D%7BI_2%7D%20%3D4%5E2%20%5C%5C%5C%5C%20I_2%3D%20%5Cfrac%7B2%7D%7B16%7D%20%5C%5C%5C%5C%20%20I_2%3D%200.125%20%5C%20foot-candles)
Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles
To learn more about the distance refer to the link;
brainly.com/question/26711747
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Answer:
Formation of new elements
Explanation:
Answer:
The answer is A good luck :P
(a) The average speed from A to B would be 1.76 metre per second and the average velocity from A to B would also be 1.76 metre per second
<span>(b) The average speed from A to C would be 1.73 metre per second and the average velocity from A to C would be 0.87 metre per second</span>