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3 years ago

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A bowling ball (mass = 7.2 kg, radius = 0.11 m) and a billiard ball (mass = 0.38 kg, radius = 0.028 m) may each be treated as un

iform spheres. What is the magnitude of the maximum gravitational force that each can exert on the other?

1 answer:

Semenov [28]3 years ago

3 0

Answer:

Explanation:

Given that

Mass of bowling ball M1=7.2kg

The radius of bowling ball r1=0.11m

Mass of billiard ball M2=0.38kg

The radius of the Billiard ball r2=0.028m

Gravitational constant

G=6.67×10^-11Nm²/kg²

The magnitude of their distance apart is given as

r=r1+r2

r=0.028+0.11

r=0.138m

Then, gravitational force is given as

F=GM1M2/r²

F=6.67×10^-11×7.2×0.38/0.138²

F=9.58×10^-9N

The force of attraction between the two balls is

F=9.58×10^-9N

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Percentage change in tension is 3.8%

Explanation:

We have given initially frequency $f_1$ = 440 Hz

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A rope with a mass density of 1 kg/m has one end tied to a vertical support. You hold the other end so that the rope is horizont

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A string with a length of 4.00 m is held under a constant tension. The string has a linear mass density of \mu=0.000600~\text{kg

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Answer:

$T=245.76N$

Explanation:

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