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zhenek [66]
3 years ago
7

A bowling ball (mass = 7.2 kg, radius = 0.11 m) and a billiard ball (mass = 0.38 kg, radius = 0.028 m) may each be treated as un

iform spheres. What is the magnitude of the maximum gravitational force that each can exert on the other?
Physics
1 answer:
Semenov [28]3 years ago
3 0

Answer:

Explanation:

Given that

Mass of bowling ball M1=7.2kg

The radius of bowling ball r1=0.11m

Mass of billiard ball M2=0.38kg

The radius of the Billiard ball r2=0.028m

Gravitational constant

G=6.67×10^-11Nm²/kg²

The magnitude of their distance apart is given as

r=r1+r2

r=0.028+0.11

r=0.138m

Then, gravitational force is given as

F=GM1M2/r²

F=6.67×10^-11×7.2×0.38/0.138²

F=9.58×10^-9N

The force of attraction between the two balls is

F=9.58×10^-9N

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A car speeds past a stationary police officer while traveling 135 km/h. the officer immediately begins pursuit at a constant acc
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(a) The time it takes for the police officer to catch up to the speeding car is determined as 0.31 s.

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<h3>Time of motion of the police</h3>

The time taken for the police to catch up with the driver is calculated as follows;

v = at

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t = v/a

t = 37.5/3.278

t = 11.4 seconds

(v1 - v2)t = ¹/₂at² --- (1)

(v1 - v2)t = v1²/2a --- (2)

From (1):

(v1 - 37.5)t = ¹/₂(3.278)t²

(v1 - 37.5)t = 1.639t²

v1 - 37.5 = 1.639t

v1 = 1.639t + 37.5  -----(3)

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(v1 - 37.5)t = v1²/(2 x 3.278)

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(1.639t + 37.5 - 37.5)t = 0.153

1.639t² = 0.153

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t = 0.31 s

<h3>Speed of the police officer</h3>

v1 = 1.639(0.31) + 37.5 = 38 m/s = 136.8 km/h

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4 0
2 years ago
The length of a certain wire is doubled and at the same time its radius is also doubled. What is the new resistance of this wire
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Answer:

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R = ρL/πr²   --------------- equation 1

Now, the new wire has:

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